Answer:
5.4 * 10^10
Step-by-step explanation:
it equals -1
you can think of it as 7-6=1 and at the end you can just add the negative sign
Hope it helps :))
The descriptions of the transformations are:
- Vertex: (-6, 0)
- Stretch factor: 2
- Domain: set of all real numbers
- Range: set of real numbers greater than or equal to 0
<h3>How to describe transformations, graph, and state domain & range using any notation?</h3>
The function is given as:
f(x) = -2|x + 6|
The above function is an absolute value function, and an absolute value function is represented as:
f(x) = a|x - h| + k
Where
Vertex = (h, k)
Scale factor = a
So, we have:
a = -2
(h, k) = (-6, 0)
There is no restriction to the input values.
So, the domain is the set of all real numbers
The y value in (h, k) = (-6, 0) is 0
i.e.
y = 0
Because the factor is negative (-2), then the vertex is a minimum
So, the range is all set of real numbers greater than or equal to 0
Hence, the descriptions of the transformations are:
- Vertex: (-6, 0)
- Stretch factor: 2
- Domain: set of all real numbers
- Range: set of real numbers greater than or equal to 0
Read more about absolute value function at
brainly.com/question/3381225
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Answer:
a= 7b
Step-by-step explanation:
a=7
b=1
a->7=7b(1)
a=7(1)
a=7
7=7
We can represent the pizza as 1. And every time we take a slice, we take percentage away. This pizza is cut up equally into 10 slices. So, if we take away a slice, we take away 1/10 of the pizza. What if Sally ate 6 slices? Same difference. She took away 6/10 of the pizza.
And to answer the question, "What <span>percentage of the pizza did Sally eat if she had six slices?"
We will convert the 6/10 into a percentage. First convert the fraction into a decimal then into a percent.
To convert a fraction into a decimal, simply divide it's numerator by it's denominator.
6/10 = 0.60
And to convert a decimal into a percentage, move the decimal point two places to the right and change it into a % sign.
0.60 = 60%
So, the answer to this question C) 60%
If you are still confused, DM me and I'll do my best to help!
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