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hodyreva [135]
2 years ago
15

What is the sum of the solutions of the 2 equations? 4x = 12 & 2y + 10 = 22

Mathematics
1 answer:
KengaRu [80]2 years ago
4 0

Answer:

x = 3 & y = 6

Step-by-step explanation:

4x = 12

12/4 = 3

x = 3

2y + 10 = 22

22 - 10 = 12

12/2 = 6

y = 6

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What value of x makes the equation true?<br> x+41=-90<br><br> i need help
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Answer:

Step-by-step explanation:

x+41=-90 (original problem)

-41     -41 (you must get rid of the common factors by doing the opposite on both sides)

x= -132 (add -90 and -41 to get -132)

6 0
2 years ago
Jenna borrowed $5,000 for 3 years and had to pay $1,350 simple interest at the end of that time. What RATE of interest did she p
mote1985 [20]

Answer:

Simple Interest =PRT/100

Rate= I ×100/PT

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135000/15000

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7 0
2 years ago
Subtract these polynomials.
zvonat [6]
Answer: A

Explanation:

(6x^2 - x + 8) - (x^2 + 2)
6x^2 - x + 8 - x^2 - 2
= 5x^2 - x + 6

6 0
3 years ago
Someone please help me
Lilit [14]
<h3>Answer:</h3>
  1. C. (9x -1)(x +4) = 9x² +35x -4
  2. B. 480
  3. A. P(t) = 4(1.019)^t

Step-by-step explanation:

1. See the attachment for the filled-in diagram. Adding the contents of the figure gives the sum at the bottom, matching selection C.

2. If we let "d" represent the length of the second volyage, then the total length of the two voyages is ...

... (d+43) + d = 1003

... 2d = 960 . . . . . . . subtract 43

... d = 480 . . . . . . . . divide by 2

The second voyage lasted 480 days.

3. 1.9% - 1.9/100 = 0.019. Adding this fraction to the original means the original is multiplied by 1 +0.019 = 1.019. Doing this multiplication each year for t years means the multiplier is (1.019)^t.

Since the starting value (in 1975) is 4 (billion), the population t years after that is ...

... P(t) = 4(1.019)^t

7 0
3 years ago
The coefficients corresponding to k = 0, 1, 2, ..., 6 in the expansion of (x + y)^6 are _____.
Kryger [21]
Using the triangle of pascal we have that the expression equivalent to (x + y) ^ 6 is given by:
 x ^ 6 + 6x ^ 5y + 15x ^ 4y ^ 2 + 20x ^ 3y ^ 3 + 15x ^ 2y ^ 4 + 6xy ^ 5 + y ^ 6
 Therefore, the coefficients of the expansion are given by:
 1, 6, 15, 20, 15, 6, 1
 Answer:
 
The coefficients corresponding to k = 0, 1, 2, ..., 6 in the expansion of (x + y) ^ 6 are 1, 6, 15, 20, 15, 6, 1
5 0
3 years ago
Read 2 more answers
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