For every 1 girl in Mr Hegarty's class there are 2 boys. What is the ratio of boys to girls in the class?

A number n plus 8 is greater than 11? What is the inequality and the solution?

fomenos

Answer:

n+8 > 11

subtract 8 from 11

n>3

7 0

3 years ago

Read 2 more answers

How do you do this i totaly forgot.

vagabundo [1.1K]

Step-by-step explanation:

7^2+8^2=113

Then square root 113 which is 10.63 to 2.d.p

So x=10.63

5 0

2 years ago

Please help me with 3.2

Lady_Fox [76]

The measure of the angle ∠PQR is 90 degrees

<h3>How to prove that ∠PQR is 90 degrees?</h3>

The equation of the line PQ is given as:

3x - y - 2 = 0

The coordinates of the QR are given as:

(0, -2) and (6, -4)

Make y the subject in 3x - y - 2 = 0

y = 3x - 2

The slope of the above line is

m1 = 3

Next, we calculate the slope (m2) of points Q and R.

So, we have:

m2 = (y2- y1)/(x2 - x1)

This gives

m2 = (-4 + 2)/(6 - 0)

Evaluate

m2 = -1/3

The slopes of perpendicular lines are opposite reciprocals.

m1 = 3 and m2 = -1/3 are opposite reciprocals.

This means the lines PQ and QR are perpendicular lines.

The angle at the point of perpendicularity is 90 degrees

Hence, the measure of the angle ∠PQR is 90 degrees

Read more about linear equations at:

brainly.com/question/15602982

#SPJ1

4 0

2 years ago

what �is the equation of a line that is perpendicular to the line y = − 2 5 x − 5 y = - 2 5 x - 5 and passes thr

gladu [14]

Answer:

$y=\frac{1}{25}x-\frac{31}{25}$

Step-by-step explanation:

$y=-25x-5$

You can get the gradient of the line perpendicular to this as you know the products of their gradients will be -1.

$-25*m_{perpendicular}=-1\\m_{perpendicular}=\frac{1}{25}$

We have a gradient, and a point (6, 1), so we can now substitute our known values into the line equation.

$(y-y_0)=m(x-x_0)$

$y-1=\frac{1}{25} (x-6)$

Rearrange for y and collect terms.

$y=\frac{1}{25}x-\frac{6}{25}-1\\\\y=\frac{1}{25}x-\frac{31}{25}$

8 0

3 years ago

Please answer 26 and 27 please thank you

ser-zykov [4K]

Answer:

Part 26) $3\frac{1}{4}\ in$

Part 27) $2\frac{2}{3}\ cups$

Step-by-step explanation:

Part 26)

we know that

The length of Alana's hair was 9 3/4 inches

After her haircut, the length was 6 1/2 inches

To find out how many inches did she have cut subtract 6 1/2 from 9 3/4

but first

Convert mixed number to an improper fraction

$9\frac{3}{4}\ in=\frac{9*4+3}{4}=\frac{39}{4}\ in$

$6\frac{1}{2}\ in=\frac{6*2+1}{2}=\frac{13}{2}\ in$

Find the difference

$\frac{39}{4}-\frac{13}{2}=\frac{39-26}{4}=\frac{13}{4}\ in$

Convert to mixed number

$\frac{13}{4}\ in=\frac{12}{4}+\frac{1}{4}=3\frac{1}{4}\ in$

Part 27)

we have that

Emeril used a total of 7 1/4 cups of flour to make three pastries

He used 2 1/4 cup of flour for the first and 2 1/3 cups of flour for the second

To find out how much cups of flour Emeril use for the third pastry, subtract the sum of the cups of flour used in the first and second pastry from the total cups of pastry used

Let

x ----> number of cups of flour used in the third pastry

$x=7\frac{1}{4}-(2\frac{1}{4} +2\frac{1}{3})$

but first

Convert mixed number to an improper fraction

$7\frac{1}{4}\ in=\frac{7*4+1}{4}=\frac{29}{4}\ cups$

$2\frac{1}{4}\ in=\frac{2*4+1}{4}=\frac{9}{4}\ cups$

$2\frac{1}{3}\ in=\frac{2*3+1}{3}=\frac{7}{3}\ cups$

substitute

$x=\frac{29}{4}-(\frac{9}{4} +\frac{7}{3})$

$x=\frac{20}{4} -\frac{7}{3}$

$x=\frac{20*3-7*4}{12}$

$x=\frac{32}{12}\ cups$

Simplify

$x=\frac{8}{3}\ cups$

Convert to mixed number

$\frac{8}{3}=\frac{6}{3}+\frac{2}{3}=2\frac{2}{3}\ cups$

4 0

2 years ago