Answer:
$848
Step-by-step explanation:
Calculation for the cost of this familiy's clothing in 1991
First step is to calculate the amount that is increase per year
Increase per year= ($1000-$620)/(1995-1985)
Increase per year= 380/10
Increase per year= $38
Now let y be :38*x + $620 and let x be 6 years (1991-1985)
Second step is to calculate the cost of the clothing in 1991
y = 38*6 + 620
y=228+620
y = $848
Therefore the cost of this familiy's clothing in 1991 will be $848
The answer is D. The ones on the left are the domain. The ones on the right which the arrows point to are the range
Reorder both sides
3y-6x=9
7-4y-3x=9
Multiply both sides
-6x-3y=9
6x+8y=-4
Dived both sides
11y= 5
Y=5/11
Substitute the value of Y
-3x-4(5/11)
Equals —> -14/11
Answer : (5/11 , -14/11)
1 liter = 1000mL
Divide 1000mL by mL per minute:
1000 / 5 = 200 minutes ( 3 hours and 20 minutes)
