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Sonja [21]
3 years ago
11

Choose the correct solution and graph for the inequality z-6 less than or equal to -14

Mathematics
1 answer:
konstantin123 [22]3 years ago
7 0
Z less than or equal to -8
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What type of angles are <2 and <7
Ivanshal [37]

Answer:

alternate exterior angles

Step-by-step explanation:

hope this helps

7 0
3 years ago
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Find the value of xxx in the isosceles triangle shown below.
MAXImum [283]

Answer:

X = 10

Step-by-step explanation:

if we say 1/2 base = <em>a</em>

a² = 13² - 12²

a² = 25

a = √25

a = 5

if 1/2 base = 5 then x = a × 2

hence X = 5 × 2 = 10

7 0
2 years ago
Can someone help with this problem please? Thanks.
Zarrin [17]
First, find the slope of the line. Use the two points given, (-4,0) and (4,2), in the slope formula rise over run. The change in rise is 2 and the change in run is 8, meaning that the slope is 2/8, simplified to 1/4. The y-intercept is 1, shown by the graph and the dashed line and shaded area means that the inequality symbol must be <. Slope-intercept form is shown as y = mx + b, so after putting our information in to the equation the answer is y < 1/4x + 1. Hope this helps!
6 0
3 years ago
PLEASE help with these questions??<br> there are 7 of them!<br> Thank you!!
svetlana [45]
We know in these kind of triangles that have a 90 degrees angle, we can do:

{a}^{2} + {b}^{2} = {c}^{2}

so the first question:

\sqrt{ {99}^{2} + {20}^{2} } = 101

and then:

b = \sqrt{ {17}^{2} - {15}^{2} } = 8

so , when you want to rationalize , usually you must multiply the irrational factor as 1:

\frac{ \sqrt{15} }{ \sqrt{15} } = 1

so , now multiply:

\frac{3}{ \sqrt{15} } \times \frac{ \sqrt{15} }{ \sqrt{15} } = \frac{3 \sqrt{15} }{15} = \frac{ \sqrt{15} }{5}

in the next question,we know negative numbers in radical don't have any solution so 2 is correct,

4 0
3 years ago
A relay race covers 1 1/2 miles, and each runner on a team will run 1/4 of a mile. How many runners are needed for a team?
Semenov [28]
6 runners are needed for the team 
8 0
3 years ago
Read 2 more answers
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