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Sonja [21]
3 years ago
11

Choose the correct solution and graph for the inequality z-6 less than or equal to -14

Mathematics
1 answer:
konstantin123 [22]3 years ago
7 0
Z less than or equal to -8
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Naiomis fish is 40 mm long her guinea pigis 25cm long
dimaraw [331]

Answer:

1,000

Step-by-step explanation:

If your asking for the area you multiply 40 times 25

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3 years ago
I need help pls due tomorrow pls I just need part B done plsss
lara [203]

Part A

1 day = 1/4 hours of practice

7 days = 7/4 hours of practice (multiply both sides by 7)

1 week = 7/4 hours of practice

1 week = (4+3)/4 hours of practice

1 week = (4+3)/4 hours of practice

1 week = (4/4)+(3/4) hours of practice

1 week = 1+(3/4) hours of practice

1 week = 1 & 3/4 hours of practice

side note: 1 & 3/4 = 1.75

=======================================

Part B

Take the result from part A, and multiply it with 60

So we'll have 60 times 1&3/4 on the left side on the first line, then 60*(1+3/4) on the right side of this same line.

The rest of the lines look like this

(60*1) + (60*3/4)

60 + 60*3/4

60 + 180/4

60 + 45

105 minutes

8 0
3 years ago
A digital picture is made up of many small dots called pixels. Rayma has a picture that is 40 pixels wide and wants to enlarge i
Xelga [282]
The answer to your question is w =40(2)n [n is in exponent form I just couldn’t type it that way ]
4 0
3 years ago
Can someone please help me answer these questions that are attached to the paper and the steps? Thanks in advance!!
Svetach [21]
Do lulus way. If you change the angles, you will not have a pentagon anymore. If you subtract, it wouldn’t be the same ratio:)
8 0
3 years ago
A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1
Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given  : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find :  transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then   Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

4 0
3 years ago
Read 2 more answers
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