2m(3m² + 4m + 6) box method and standard form I don’t get it
2 answers:
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Answer: 21
Step-by-step explanation:
Given: Number of mango guava and sapota are supplied 108,84 and 60 respectively.
Since, 108 = 2 x 2 x 3 x 3 x 3
84 = 2 x 2 x 3 x 7
60 = 2 x 2 x 3 x 5
HCF(108,84,60) = 2 x 2 x 3 [HCF=Highest common factors]
= 12
Greatest number of plants in each row = 12
Number of rows for mango =
Number of rows for guava =
Number of rows for sapota =
Total rows = 9+7+5= 21
Hence, the minimum number of rows in which they can be planted if in each row same numbers of saplings of the same type are to be planted = 21