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faltersainse [42]
3 years ago
13

Reduce improper 24/5

Mathematics
1 answer:
iogann1982 [59]3 years ago
6 0
The answer is 4 4/5
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17 + 15 + 26 = 58  (he wants 58 tickets)

22 - 8 = 14 (he has 14 tickets)

58 - 14 = 44 (he needs 44 tickets)
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6(x – 1) = 9(x + 2) what is the answer
const2013 [10]

Answer:

The answer is x = -8

6 0
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You are trying to find the distance from Saint Augustine to Jacksonville. What would be the most appropriate unit of measure to
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it is kilometers

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1. Two object accumulated a charge of
In-s [12.5K]

Answer:

The  magnitude of the electric force  between these two objects

will be: 181.274 N.

i.e.  F  =181.274 N

Step-by-step explanation:

As

Two object accumulated a charge of  4.5 μC and another a charge of 2.8  μC.

so

q₁ = 4.5 μC = 4.5 × 10⁻⁶ C

q₂ = 2.8  μC = 2.8 × 10⁻⁶  C

separated distance = d = 2.5 cm

Calculating the magnitude of the force between two charged objects using the formula:

F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}

   =\:\frac{4.5\times \:\:10^{-6}\:\times \:\:2.8\:\times \:\:10^{-6}}{4\:\times \:\left(3.14\right)\:\times \:\left(8.85\times \:10^{-12}\right)\times \left(2.5\times \:\:10^{-2}\right)^2}

   =\frac{10^{-12}\times \:12.6}{10^{-12}\times \:4\times \:8.85\pi \left(10^{-2}\times \:2.5\right)^2}        ∵ 4.5\times \:10^{-6}\times \:2.8\times \:10^{-6}=10^{-12}\times \:12.6

   =\frac{10^{-12}\times \:12.6}{10^{-12}\times \:35.4\pi \left(10^{-2}\times \:2.5\right)^2}    ∵ \mathrm{Multiply\:the\:numbers:}\:4\times \:8.85=35.4

\mathrm{Cancel\:the\:common\:factor:}\:10^{-12}

  =\frac{12.6}{35.4\pi \left(10^{-2}\times \:2.5\right)^2}

  =\frac{12.6}{0.025^2\times \:35.4\pi }        ∵ \left(10^{-2}\times \:2.5\right)^2=0.025^2

  =\frac{12.6}{0.022125\pi }        ∵ 35.4\pi\times 0.025^2=0.022125\pi

   =\frac{12.6}{0.06950 }

F  =181.274 N

Therefore, the  magnitude of the electric force  between these two objects will be: 181.274 N.

i.e.  F  =181.274 N

7 0
3 years ago
Given a circle with a radius of 6, what the the length of an arc measuring 30 degrees
Mazyrski [523]
\bf \textit{arc's length}\\\\
s=\cfrac{\theta \pi r}{180}\quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
r=6\\
\theta =30
\end{cases}\implies s=\cfrac{30\cdot \pi \cdot 6}{180}\implies s=\pi
6 0
3 years ago
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