The given data is
t, h: 0 2 4 6 8 10
r(t), L/h: 8.6 7.9 6.8 6.4 5.7 5.3
The lower and upper estimates for the total amount that leaked may be computed as the Left and Right Riemann sums.
The shape of the graph of r versus will determine which of the two sums yields an upper or lower sum.
The plot of the graph is shown below.
The Left Riemann sum is
Sl = 2*(8.6+7.9+6.8+6.4+5.7) = 70.8 L
The Right Riemann sum is
Sr = 2*(7.9+6.8+6.4+5.7+5.3) = 64.2 L
Answer:
The lower estimate for oil leakage is 64.2 L
The upper estimate for oil leakage is 70.8 L
Answer: y=1/2x+4
Step-by-step explanation:
1. y-y1=m(x-x1)
2.y-5=1/2(x-2)
3. solve
4. y-5=1/2x-1
5. add 5 to both sides to isolate the variable
6. this gives you y=1/2x+4
What it is asking is 8 times what equals 48. The best way to do this is by doing the opposite operation. 48 divided by 8 equals 6. Then if you put it in the other way you get 8(6)=48 which works out. So the answer is 6.
81 because 81 is a perfect square and 27 times 3 =81