Let's think about the information in the problem. The problem tells us a few key points:
- The number of rabbits grows exponentially
- We start with 20 rabbits (
, 
) - After 6 months (
), we have 100 rabbits (
)
Since we know we are going to be working with an exponential model, we can start with a base exponential model:
is the principal, or starting amount
is the growth/decay rate (in this case, growth)
is the number of months
is the number of rabbits
Based on the information in the problem, we can create two equations:
The first equation tells us that 
, or that we start with 20 rabbits. Thus, we can change the second equation to:
Now, we don't know , but we want to, so let's solve for it.
![r = \sqrt[6]{5}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B6%5D%7B5%7D)
Now, the problem is asking us how many rabbits we are going to have after one year (
), so let's find that:
![a = 20 \cdot (\sqrt[6]{5})^{12}](https://tex.z-dn.net/?f=a%20%3D%2020%20%5Ccdot%20%28%5Csqrt%5B6%5D%7B5%7D%29%5E%7B12%7D)
After one year, we will have 500 rabbits.
Answer:
60 dollars. I hipe this helps
Answer:
-1 i think
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
Exponential growth/decay rule with general function is:<span>y=y(0)<span>e<span>kt</span></span></span>
with k is growth/decay constant rate.
(1) Deer population function
y(0) = 1253
k
= 3%
t
= 6 (years)
y(6) = 1253 . e^(0.03*6) ~ 1500 (deers)
: 1496 deers
(2) Growth factor b is rate 9.5% = 0.095
