I believe it would be 6. the first number and exponent are usually your quadratic terms
Answer:
(2, - 3 )
Step-by-step explanation:
Given the 2 equations
y = - 3x + 3 → (2)
y = - 9x + 15 → (2)
Substitute y = - 3x + 3 into (2)
- 3x + 3 = - 9x + 15 ( add 9x to both sides )
6x + 3 = 15 ( subtract 3 from both sides )
6x = 12 ( divide both sides by 6 )
x = 2
Substitute x = 2 into either of the 2 equations and solve for y
Substituting into (1)
y = - 3(2) + 3 = - 6 + 3 = - 3
solution is (2, - 3 )
Answer:
Step-by-step explanation:
Part A.
Expression 
= 10
Because 100 = 
and ![[(10)^2]^{\frac{1}{2}}=10^1=10](https://tex.z-dn.net/?f=%5B%2810%29%5E2%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%3D10%5E1%3D10)
[Since, 
]
Part B.
When simplified, the answer is RATIONAL.
[Since, 10 can be written as 
]
For this case we have the following equation:
By completing squares we have:
Step 1:
Add 
on both sides:
Step 2:
We rewrite the equation:
Step 3:
We solve the equation:
Solutions:
Answer:
the next line would be:
Answer: To determine if two lines are parallel or perpendicular, you have to look at the slopes. For the line y=kx+b, k is the slope.
For two lines y=k1x+b1 and y=k2X+b2 ,When K1=K2, two lines are parallel; when K1=-1/k2, two lines are perpendicular. It doesn't matter whatever b1, b2 are. Hence to save time, you only need to calculate k1 and k2.
To calculate the slope k of any line, you have to change the equation to y=kx+b
For -y=3x-2, k=3/(-1)=-3 (you divide -1 on each side of =, but you don't need to calculate -2/(-1))
For -6X+2y=6, K=6/2=3 (you first move the -6x to right side, it becomes 6x, then divide by 2)
Now you can get the answer: The two lines neither parallel nor perpendicular.
