Question

What is the period t of the function y=3sin(4t)?

Answer 1

The period = 2pi/4 = pi2=1.571
Good luck

Answer 2

Answer:

$\frac{\pi}{2}$

Step-by-step explanation:

We are given that a function

$y=3 sin(4t)$

We have to find the period t of the given function.

To find the period of given function we will compare with general sine function equation period.

$f(x) =A sin(Bx+C)+D$

Period=$\frac{2\pi}{\mid B\mid}$

By comparing we get

$\mid B\mid=4$

Substitute the value  in the given formula to finding the period

Then ,we get the  period t of given function=$\frac{2\pi}{4}=\frac{\pi}{2}$

Hence, the period of given function =$\frac{\pi}{2}$