Question

Solve (-4/3*pi*rˆ3*x) + (4*pi*rˆ2*y)

Answer 1

Answer:

$(-\frac{4}{3}\pi r^3 x)+(4\pi r^2y)=4\pi r^2(-\frac{1}{3}rx+y)$

Step-by-step explanation:

$(-\frac{4}{3}\pi r^3 x)+(4\pi r^2y)\\\\=[4\pi r^2\times (-\frac{1}{3}rx)]+[4\pi r^2y]\\\\4\pi r^2\ is\ common\ in\ both\ expression\\\\ =4\pi r^2(-\frac{1}{3}rx+y)\\\\(-\frac{4}{3}\pi r^3 x)+(4\pi r^2y)=4\pi r^2(-\frac{1}{3}rx+y)$