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fgiga [73]
3 years ago
13

What constants do you need to add to each of the following quadratic equations to complete the square? 2x2 - 3x = 0 x2 - 8x = 0

2x2 - 11x = 18
Mathematics
1 answer:
Oduvanchick [21]3 years ago
7 0
1.) x= 4/3
2.) x= 0
3.) x= -14/11
Hope this helps sorry if not
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Element X is a radioactive isotope such that every 5 years, its mass decreases by half.
Verdich [7]

Answer: 24 grams of element would remain.

Step-by-step explanation:

Exponential function for decay:

f(x)=Ab^{\frac{x}{n}} ....(i) , where A = initial value , b = decay factor, x = time , n= time per period

As per given,

A = 569 grams , b=\dfrac12

n= 5 years, t = 23 years

Put all values in (i) , we get

f(23)=590(\dfrac12)^{\frac{23}{5}}\\\\\\=590\times 0.0412346222117\\\\=24.3284271049\approx 24

Hence, after 23 years , 24 grams of element would remain.

6 0
3 years ago
Can someone please help me?<br> MATH...ANSWER ALL QUESTIONS!!! 50 POINTS!!!
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7 0
3 years ago
Ther are 330 walnuts in 6 bags if each bag has the same number of walnuts how many walnuts are in 2 bags
Serhud [2]

Answer:

110 Walnuts

Step-by-step explanation:

Firstly, there are 6 bags and 330 walnuts. You divide 330 by 6 and you get 55. 330/6. Now, you multiply 55 by 2 and you get your answer. So basically in each bag there are 55 walnuts and if you multiply that by 6 you get 330 again. Hope this helped!

3 0
3 years ago
Find the principal that will yield a simple interest of Rs 9000 in 5 years at a rate of 6% per annum.
damaskus [11]

9514 1404 393

Answer:

  ₹ 30000

Step-by-step explanation:

The simple interest formula is ...

  I = Prt . . . . . . principal P invested at rate r for t years

Fill in the values you know, and solve for the one you don't know.

  9000 = P(0.06)(5)

  9000/0.30 = P = 30000

The principal that will give ₹9000 in interest is ₹30000.

4 0
3 years ago
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The triangles below are congruent and the corresponding parts are marked
Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

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2 years ago
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