The easiest variable you can solve for first is "z". Knowing that opposite angles of a quadrilateral inscribed in a circle are supplementary, subtract 93 from 180 to get z.
Z should equal 87.
The next variable we can solve for is "x". We know that inscribed angles are half the measure of their intercepting arc, so we know 93 is half of (112 + x). The equation would look like this:
93= (112 + x)/2
Multiply both sides by 2
186 = 112 + x
Subtract 112 from both sides
74 = x
Now we can apply the same method we used to find "x" to find y. Set up an equation like this:
80 = (y + x)/2
Substitute the value of x in
80 = (y + 74)/2
Multiply both sides by 2
160 = y + 74
Subtract 74 from both sides
86 = y
Hope this helps!
The answer's 2.2
I'm sorry I can't show you, but LaTex doesn't allow you to show short division.
You can find out how to do it here, on Wikipedia's page. https://www.wikiwand.com/en/Short_division
Answer:
−438°, -78°, 642°
Step-by-step explanation:
Given angle:
282°
To find the co-terminal angles of the given angle.
Solution:
Co-terminal angles are all those angles having same initial sides as well as terminal sides.
To find the positive co-terminal of an angle between 360°-720° we will add the angle to 360°
So, we have: 
To find the negative co-terminal of an angle between 0° to -360° we add it to -360°
So, we have: 
To find the negative co-terminal of an angle between -360° to -720° we add it to -720°
So, we have: 
Thus, the co-terminal angles for 282° are:
−438°, -78°, 642°
9514 1404 393
Answer:
7.5 square units
Step-by-step explanation:
The formula for the area of a trapezoid is ...
A = 1/2(b1 +b2)h
where b1 and b2 are the lengths of the parallel bases, and h is the perpendicular distance between them.
Here, the bases are TR = 1 and PA = 4. The height is 3 units, so the area is ...
A = (1/2)(1 +4)(3) = 15/2 = 7.5 . . . . square units
