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JulijaS [17]
3 years ago
8

How to graph this? Please asap

Mathematics
1 answer:
iVinArrow [24]3 years ago
4 0
I hope this helps you

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Help please <br> 20 characters long.
Svet_ta [14]

Hope you could understand.

If you have any query, feel free to ask.

8 0
3 years ago
"Polio has a basic reproduction number (R0) = 5. The vaccine is very good; in fact, polio vaccine is 99% effective when two foll
yulyashka [42]

Answer:

0.81

Step-by-step explanation:

Herd immunity or community immunity is the immunity seen after vaccination of a population wherein the large portion of the population becomes immune to the pathogen. It depends on vaccine efficacy and vaccination rate.

The reproduction number R_o is a factor indicating the number of people that can be infected by the person with the disease. If Ro=5 then one infected person can infect 5 people with Polio virus.

V_c= q_c/E

V_c= Vaccine coverage

q_c= herd immunity threshold

E= Vaccine efficacy= 99%=0.99

q_c=1-1/R_o= 1-1/5=0.8

V_c= q_c/E

V_c= 0.8/0.99= 0.808= 0.81

Thus, 81% coverage or vaccination for Polio is required to stop spread of Polio in the population.

5 0
3 years ago
Using the figure below, find the value of x. Enter your answer as a simplified radical or improper fraction (if necessary) into
Veronika [31]

Hello,

M=middle[AB]

The triangle ABC is equilateral :

x= 15/2

3 0
3 years ago
4x+3 =23<br>2x - 10 = -32<br>- 4x + 1 = -27<br>6x - 2 = -20​
Scrat [10]

Answer:

1)x = 5

2)× = -11

3)x = 7

4)x = 3.66

7 0
3 years ago
The half-life of cesium-137 is 30 years. Suppose we have a 20 mg sample.
Tju [1.3M]

Answer:

(a) A = (20mg)/(2^(t/30))

(b) 12.6mg

(c) 129.6years

Step-by-step explanation:

To calculate the amount remaining after a number of half-lives, n, we can make use of:

A = \frac{B}{2^n}

Where A = amount remaining

B = initial amount

n = \frac{t}{t_{0.5}}

(a) A = (20mg)/(2^(t/30))

(b) Mass after 20years

A = (20mg)/(2^(20/30)) ≈ 12.6mg

(c) After how long will only 1mg remain:

1mg = (20mg)/(2^(t/30))

20mg = {2^{\frac{t}{30}}

Taking log of both sides we have:

Log(20) = (t/30)log(2)

t/30 = (log(20))/(log(2)) ≈ 4.3

t/30 = 4.3

t = 30 x 4.3 ≈ 129.6years.

8 0
3 years ago
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