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Burka [1]
3 years ago
12

“Teachers gave 18.5% more homework in 2007 than in 2005.”

Mathematics
1 answer:
777dan777 [17]3 years ago
4 0
That is because The curiculem changes with time. 
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Do more than 50 percent of the children in a certain group have brown hair?
babymother [125]

Answer:

What we know is that 30% of the group have brown hair and are girls. It means that in the other 70% we have the boys with brown hair, the other boys and the other girls.

In the case all the girls have brown hair, the 70% remaining would be boys. So 70% of then would have brown hair. (0.7*0.7=0.49 -> 49% of the children would be brown hair) so 49% (boys) and 30% (girls) are more than 50%..

Now, let's suppouse that 90% of the group are girls. It means 10% are boys and 70% of that 10% (=7%) are the boys in the group that have brown hair. Now 7% + 30% of the children have brown hair, wich isn't more than the half.

We have explained with two extreme cases that the information is not enough for making a precise answer

7 0
3 years ago
Help me pleasee this is to confusing.
AVprozaik [17]

Answer:

What's confusing ??? You literally just put a dot on the number line

Example:

1.3, move 3 units to the right of 1 and place a dot there

5 0
3 years ago
What number is 1/10 as great as 7962?
koban [17]
796.2 abhajdhhsgsgdh
5 0
3 years ago
Suppose that det(a) = a b c d e f g h i = 2 and find the determinant of the given matrix. a b c −4d −4e −4f a + g b + h c + i
zhuklara [117]
I'll go out on a limb and suppose you're given the matrix

\mathbf A=\begin{bmatrix}a&b&c\\d&e&f\\g&h&i\end{bmatrix}

and you're asked to find the determinant of \mathbf B, where

\mathbf B=\begin{bmatrix}a&b&c\\-4d&-4e&-4f\\a+g&b+h&c+i\end{bmatrix}

and given that \det\mathbf A=2.

There are two properties of the determinant that come into play here:

(1) Whenever a single row/column is scaled by a constant k, then the determinant of the matrix is scaled by that same constant;

(2) Adding/subtracting rows does not change the value of the determinant.

Taken together, we have that

\det\mathbf B=-4\det\mathbf A=-8
5 0
4 years ago
Supposethat z is a normally distributed variable with variance 4. You collect a sample of size n for which you get a sample aver
Nikitich [7]

Answer:

The sample size is 4

Step-by-step explanation:

Null hypothesis: The mean is 2

Alternate hypothesis: The mean is less than 2

Mean = 3

sd = sqrt(variance) = sqrt(4) = 2

At 95% confidence level, t-value is 1.960

Assuming the lower bound of the mean is 1.04

Lower bound = mean - (t×sd/√n)

1.04 = 3 - (1.96×2/√n)

3.92/√n = 3 - 1.04

3.92/√n = 1.96

√n = 3.92/1.96

√n = 2

n = 2^2

n = 4

7 0
3 years ago
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