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2 years ago

Mikayla earns $ 100 every 8 hours at her new job. At

Mathematics

1 answer:

spin [16.1K]2 years ago

6 0

Answer:

$175

Step-by-step explanation:

100 divided by 8 is 12.5

12.5 x 14 is 175.

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An algebraic expression for 2 times a number plus 5

natali 33 [55]

Answer:

2x+5

Step-by-step explanation:

X represents the number in "2 times a number." You could insert any number into x.

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3 years ago

Combining like terms with negative coefficients

den301095 [7]

Answer:

you add them, but keep the sign

Step-by-step explanation:

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3 years ago

A fried chicken franchise finds that the demand equation for its new roast chicken product, "Roasted Rooster," is given by p = 4

LUCKY_DIMON [66]

Answer:

1. $q=(\dfrac{45}{p})^{\frac{2}{3}}$

2. $E_d=-\dfrac{2}{3}$

Step-by-step explanation:

The given demand equation is

$p=\dfrac{45}{q^{1.5}}$

where p is the price (in dollars) per quarter-chicken serving and q is the number of quarter-chicken servings that can be sold per hour at this price.

Part 1 :

We need to Express q as a function of p.

The given equation can be rewritten as

$q^{1.5}=\dfrac{45}{p}$

Using the properties of exponent, we get

$q=(\dfrac{45}{p})^{\frac{1}{1.5}}$ $[\because x^n=a\Rightarrow x=a^{\frac{1}{n}}]$

$q=(\dfrac{45}{p})^{\frac{2}{3}}$

Therefore, the required equation is $q=(\dfrac{45}{p})^{\frac{2}{3}}$ .

Part 2 :

$q=(45)^{\frac{2}{3}}p^{-\frac{2}{3}}$

Differentiate q with respect to p.

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(p^{-\frac{2}{3}-1}})$

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(p^{-\frac{5}{3}})$

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})$

Formula for price elasticity of demand is

$E_d=\dfrac{dq}{dp}\times \dfrac{p}{q}$

$E_d=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})\times \dfrac{p}{(45)^{\frac{2}{3}}p^{-\frac{2}{3}}}$

Cancel out common factors.

$E_d=(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})\times \dfrac{p}{p^{-\frac{2}{3}}}$

Using the properties of exponents we get

$E_d=-\dfrac{2}{3}(p^{-\frac{5}{3}+1-(-\frac{2}{3})})$

$E_d=-\dfrac{2}{3}(p^{0})$

$E_d=-\dfrac{2}{3}$

Therefore, the price elasticity of demand is -2/3.

3 0

3 years ago

A cooler contains ten bottles of sports drink: four lemon-lime flavored, three orange-flavored, and three fruit-punch flavored.

Alika [10]

Since there are a total of 10 bottles, the probability of getting a certain one is based on the number of those bottles in the cooler.

The probability of getting a lemon-lime flavored drink is 4/10 or 40%.

The probability of getting a orange flavored drink is 3/10 or 30%

The probability of getting a fruitpunch flavored drink is also 3/10 or 30%.

If the question is asking what the probability is of choosing lemon-lime, fruit punch and fruit punch again in that order, you would multiply the probabilities together.

.4 * .3 * .3 = .036, so there’s a 3.6% chance of picking these exact 3 flavors happening again.

6 0

3 years ago

Read 2 more answers

Is 145 oz bigger than 9lb

Lynna [10]

Answer:

yes 145 equals 9.0625 in lb

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers