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3 years ago

7

Mr. Buckham teaches vocabulary to 27 fourth grade Students. There are 63 new vocabulary words. Each student rights one vocabular

y and definition on an index card. Does he have enough index cards for all students ?

1 answer:

disa [49]3 years ago

6 0

Yes he has enough index cards for all students

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PLEASE help me ASAP i give brainliest!

faltersainse [42]

Answer:

scatter plot A: -0.90

scatter plot B: 0.89

scatter plot C: -0.76

scatter plot D: 0.55

Step-by-step explanation:

if the line is going down, it's negative and if it goes up it's positive. The closer the points are <em>the higher the number</em>.

HOPE THIS HELPS!!

3 0

3 years ago

Y=1/2×-6 ×=-4 what is the solution to the system of equations

hodyreva [135]

Answer:

(-4, -8)

Step-by-step explanation:

Use the substitution method. x = -4, so y = (1/2)x - 6 becomes:

y = (1/2)(-4) - 6, or y = -2 - 6, or y = -8.

The solution is (-4, -8).

8 0

3 years ago

What is the solution of the equation over the complex numbers

denis-greek [22]

<u>Answer:</u>

$2i\sqrt{3}$

$-2i\sqrt{3}$

<u>Step-by-step explanation:</u>

$x^2 + 12$

First set the equation to 0

$x^2 + 12$

$x^2 + 12 = 0$

Second, get the 12 on the right side of the equal sign by adding a -12 to each side

$x^2 + 12 = 0$

$x^2 + 12 + (-12) = 0 -12$

$x^2 = -12$

Square root both sides of the equal sign.

$x^2 = -12$

$\sqrt{x^2} = \sqrt{-12}$

Take the square root on left sides of the equal sign.

$\sqrt{x^2} = \sqrt{-12}$

$x = \sqrt{-12}$

Take the square root on the right side of the equal sign. Remember $\sqrt{-1} = i$

$x = \sqrt{-12}$

$x = \sqrt{4}*\sqrt{-1}\sqrt{3}}$

$x = 2i\sqrt{3}$

<u>AND</u>

$x = -2i\sqrt{3}$

8 0

4 years ago

Gabe rolled 14 strikes out of 70 attempts. What percent of Gabe's attempts were strikes?

Airida [17]

Answer:

20%

Step-by-step explanation:

14/70x100=20%

5 0

3 years ago

Which statements can be concluded from the diagram and used to prove that the triangles are similar by the SAS similarity theore

velikii [3]

Answer:

RS/VU=ST/UT and ∠S≅∠U

Step-by-step explanation:

we know that

The <u>Side-Angle-Side Similarity Theorem </u>states that: If two sides in one triangle are proportional to two sides in another triangle and the included angle in both are congruent, then the two triangles are similar

In this problem the included angle is

∠S≅∠U

therefore

side RS must be proportional to side VU and side ST must be proportional to side UT

so

RS/VU=ST/UT

<em>Verify</em>

substitute the given values

12/6=16/8

2=2 -----> is true

therefore

The two sides are proportional

6 0

3 years ago

Read 2 more answers