Answer:
sududueufddssiie yan sagot sure ako lagpas nako jaan ganyan sinagot ko
1 1/3 4 times like a chocolate bar
Solution:
Let the distance of house from the theater be x miles.
Total travelling time![=3.5-2.25=1.25 Hr](https://tex.z-dn.net/?f=%20%3D3.5-2.25%3D1.25%20Hr%20)
Then average speed![=\frac{Distance}{Time}= \frac{2x}{1.25}\\](https://tex.z-dn.net/?f=%20%3D%5Cfrac%7BDistance%7D%7BTime%7D%3D%20%5Cfrac%7B2x%7D%7B1.25%7D%5C%5C%20)
Terrence walks at a pace of 2 mi/h to the theater and back home at 40 mi/h.
So Average Speed
mi/hr
Both the average speed should be equal. So we can write
![\frac{2x}{1.25}=21\\ \\ 2x=1.25*21\\ \\ x=13.125\\](https://tex.z-dn.net/?f=%20%20%5Cfrac%7B2x%7D%7B1.25%7D%3D21%5C%5C%0A%5C%5C%0A2x%3D1.25%2A21%5C%5C%0A%5C%5C%0Ax%3D13.125%5C%5C%20)
Hence the distance from home is 13.125 miles.
Answer:
x = 5
Step-by-step explanation:
x^2/(x + 5) = 25/(x+5) Subtract the right side from both sides.
x^2/(x + 5) - 25/(x + 5) = 0
x^2 - 25
======= = 0
x + 5
(x + 5)(x - 5)
============= = 0
(x + 5)
Cancel x + 5 in the numerator and denominator.
x - 5 = 0
x = + 5
Does it check?
x^2/(x + 5) = 25/(x + 5)
x = 5
5^2/(10) = 25/10
25/10 = 25/10 Yes it checks.