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loris [4]
3 years ago
11

I need help with this and explain how to do it please!! 6x - 4z

Mathematics
1 answer:
Troyanec [42]3 years ago
4 0

Answer:

you should know you dont need help so do it by yourself. if you want the awnser you should know or you just dont pay attention in class.1234567890 is your awnser

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Find the quotient<br> 4/3÷1 1/12
nlexa [21]
The answer should be 1/9

8 0
2 years ago
Pls helppp!!! -------
Gelneren [198K]

Answer:

∠ A ≈ 44.42°

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos A = \frac{adjacent}{hypotenuse}  = \frac{AC}{AB} = \frac{5}{7} , then

∠ A = cos^{-1} (\frac{5}{7} ) ≈ 44.42° ( to the nearest hundredth )

5 0
3 years ago
For carolina's birthday her mom took her and her friends to a water park.Carolina mom paid 42.50 for 5 students tickets. What wa
Sophie [7]

Answer:

8.5 for each student ticket

Step-by-step explanation:

Simply divide the total cost 42.5 by the amount of students 5 to get your answer.

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7 0
3 years ago
Simplify 2√2-√3<br> ---------------<br> √2+√3
serious [3.7K]

Step-by-step explanation:

=  \frac{2 \sqrt{2}   -  \sqrt{3} }{ \sqrt{2} +  \sqrt{3}  }

=  \frac{2 \sqrt{2} -  \sqrt{3}  }{ \sqrt{2} +  \sqrt{3}  }  \times  \frac{ \sqrt{2} -  \sqrt{3}  }{ \sqrt{2} -  \sqrt{3}  }

= \frac{ 2( \sqrt{2}  -  \sqrt{3} )( \sqrt{2}  -  \sqrt{3} )}{ { \sqrt{2} }^{2} -  { \sqrt{3} }^{2}  }

=  \frac{2(2 -  \sqrt{6}  -  \sqrt{6} - 3) }{2 - 3}

=  \frac{2( - 1 - 2 \sqrt{6} )}{ - 1}

=  \frac{ - 2(1 + 2 \sqrt{6} )}{ - 1}

= 2(1 + 2 \sqrt{6} )

= 2 + 4 \sqrt{6}

6 0
2 years ago
Multiply c^2(c^2-10c+25)
Artemon [7]

Step-by-step explanation:

c^2( c^2-10c+25)

=c^4 - 10c^3 + 25c^2

8 0
3 years ago
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