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2 years ago

Graph f(x)= -0.25x+4 HELP ASAP PLEASE!!!

Mathematics

2 answers:

Alex787 [66]2 years ago

7 0

Answer:

Shown below

Step-by-step explanation:

-0.25/1x is your rise over run, 4 is your “starting point”

vitfil [10]2 years ago

3 0

Answer:

Step-by-step explanation:

1) Since this function is f(x)=mx+b, whose rule is:

$f(x)=-0.25x+4$

2) Then this parameter m is a negative one, the line is a decreasing one (from upper left to lower right). Then Let's choose three random values for x, and plug it in the function, to get y values. Let x, be 0,1,2.

The parameter b is 4 then the line crosses the y-axis in point (0,4).

3) Plugging it in, goes:

$f(x)=-0.25x+4\Rightarrow f(0)=-0.25(0)+4\Rightarrow f(0)=4\\f(1)=-0.25(1)+4\Rightarrow f(1)=-0.25(1)+4\Rightarrow f(1)=3.75\Rightarrow f(2)=-0.25(2)+4\Rightarrow f(2)=3.50$

As we have three coordinate points, we can trace a line:

(0,4),(1,3.75),(2,3.5)

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20% of what number is equal to 2/3 of 90?

blagie [28]

Let the number be x, then

1/5 * x = 2/3 * 90

1/5 x = 60

x = 60 * 5 = 300 (answer)

7 0

2 years ago

Hi guys, can anyone help me with this triple integral? Many thanks:)

Crank

Another triple integral. We're integrating over the interior of the sphere

$x^2+y^2+z^2=2^2$

Let's do the outer integral over z. z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

$y^2=4-x^2-z^2$

x is the inner integral so at this point we conservatively say its zero. That means y goes from $-\sqrt{4-z^2}$ and $+\sqrt{4-z^2}$

Similarly the inner integral x goes between $\pm-\sqrt{4-y^2-z^2}$

So we rewrite the integral

$\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz$

Let's work on the inner one,

$\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz$

There's no z in the integrand, so we treat it as a constant.

$=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}$

So the middle integral is

$\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy$

I gotta go so I'll stop here, sorry.

7 0

2 years ago

Read 2 more answers

Each week, Heather’s company has $5000 in fixed costs plus an additional $250 for each system produced. The company is able to p

kvv77 [185]

The question is an illustration of composite functions.

Functions c(n) and h(n) are $\mathbf{c(n) = 5000 + 250n}$ and $\mathbf{n(h) = 5h}$
The composite function c(n(h)) is $\mathbf{c(n(h)) = 5000 + 1250h}$
The value of c(n(100)) is $\mathbf{c(n(100)) = 130000}$
The interpretation is: "the cost of working for 100 hours is $130000"

The given parameters are:

$5000 in fixed costs plus an additional $250
5 systems in one hour of production

(a) Functions c(n) and n(h)

Let the number of system be n, and h be the number of hours

So, the cost function (c(n)) is:

$\mathbf{c(n) = Fixed + Additional \times n}$

This gives

$\mathbf{c(n) = 5000 + 250 \times n}$

$\mathbf{c(n) = 5000 + 250n}$

The function for number of systems is:

$\mathbf{n(h) = 5 \times h}$

$\mathbf{n(h) = 5h}$

(b) Function c(n(h))

In (a), we have:

$\mathbf{c(n) = 5000 + 250n}$

$\mathbf{n(h) = 5h}$

Substitute n(h) for n in $\mathbf{c(n) = 5000 + 250n}$

$\mathbf{c(n(h)) = 5000 + 250n(h)}$

Substitute $\mathbf{n(h) = 5h}$

$\mathbf{c(n(h)) = 5000 + 250 \times 5h}$

$\mathbf{c(n(h)) = 5000 + 1250h}$

(c) Find c(n(100))

c(n(100)) means that h = 100.

So, we have:

$\mathbf{c(n(100)) = 5000 + 1250 \times 100}$

$\mathbf{c(n(100)) = 5000 + 125000}$

$\mathbf{c(n(100)) = 130000}$

(d) Interpret (c)

In (c), we have: $\mathbf{c(n(100)) = 130000}$

It means that:

The cost of working for 100 hours is $130000

Read more about composite functions at:

brainly.com/question/10830110

5 0

2 years ago

I built a storage shed in the shape of a rectangular box on a square base. The material that I used for the base cost $4 per squ

Jobisdone [24]

Answer:

$\frac{a(450-8a^2)}{4}$

is the volume in terms of side a

Step-by-step explanation:

Given that you I built a storage shed in the shape of a rectangular box on a square base. The material that I used for the base cost $4 per square foot, the material for the roof cost $2 per square foot, and the material for the sides cost $2.50 per square foot; and I spent $450 altogether on material for the shed.

Let a be the side of square and h be the height

Total cost of materials = cost for floor + cost for roof + cost for sides

= area of floor (4) + lateral area (2.50)+roof area (2)

$=4a^2+4ah+4a^2\\=8a^2+4ah = 450$ $h = \frac{450-8a^2}{4a}$