For question number 1:The plot H = H(t) is the parabola and it reaches its maximum in the moment when exactly at midpoint between the roots t = 0 and t = 23. At that moment t = 23/2 or 11.5 seconds.
For question number 2:To find the maximal height, just simply substitute t = 11.5 into the quadratic equation. The answer would be 22.9.
For question number 3:H(t) = 0, or, which is the same as -16t^2 + 368t = 0.Factor the left side to get -16*t*(t - 23) = 0.t = 0, relates to the very start of the process, when the ash started its way up.The other root is t = 23 seconds, and it is precisely the time moment when the bit of ash will go back to the ground.
Answer:
ΔHFG≅ΔSUT
Step-by-step explanation:
You just have to match up the sides and the angle.It's easier to color code them.
For example:
Segment SU would be congruent with HF. (both would be blue, just example color)
Angle U is congruent to angle F (red)
UT congruent to FG (green)
Answer:
Easy!
Step-by-step explanation:
1) To find the surface area of a regular triangular pyramid, we use the formula SA = A + (3/2)bh, where A = the area of the pyramid's base, b = the base of one of the faces, and h = height of one of the faces.
or
2)Multiply the side length of the base by the slant height and divide by two. Then, multiply by 4. This will give you the lateral surface area of the pyramid. Add the base surface area and the lateral surface area.
Answer:
Please read down below, thanks
Step-by-step explanation:
Vertical angles are always equal.
Because the two expression we have are equal, we can make the equation:
4x + 2 = 5x - 13
Let's move x to one side and the constants to the other side.
Subtract both sides by 4x and add both sides by 13
15 = x
Now we know x = 15, we can solve for the angles.
∠ABC is 4x + 2 so: 4(15) + 2 = 47 degrees
∠CBE added up with ∠ABC is 180 degrees so: 180 - 47 = 133 degrees
∠DBE is the same as ∠ABC so: 47 degrees
∠ABD is also the same as ∠CBE so: 133 degrees