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3 years ago

How to find y coordinate? Here are my x coordinates and this is the given formula:

Mathematics

1 answer:

Luda [366]3 years ago

6 0

Y=x-3x+1
y=2-3(-4)+1
y=15

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Find BC if AC = 13 and AB = 10

maxonik [38]

Answer:

BC=3

Step-by-step explanation:

We can solve this by eliminating given detail of A.

AC=13 , AB=10

To find BC, We minus AC With AB

BC= AC-AB

BC=3

3 Is the final answer

I hope this helps, dont hesitate to ask for any question.

Mark me as brainliest is appreciated.Tq!!

7 0

3 years ago

A car is driving at a speed of 40 mi/h. What is the speed of the car in feet per minute? a. 2,400 ft/min b. 211,200 ft/min c. 3,

SCORPION-xisa [38]

Answer:

3520 ft/min

Step-by-step explanation:

40 mi/h = (40 mi/h)×(5280 ft/mi)×(1 h)/(60 min) = 3520 ft/min

_____

Each conversion factor has a value of 1 (numerator = denominator), so changes the units without changing the speed.

3 0

3 years ago

Given that the quadratic equation has equal roots (k^2-1)x^2-2kx-3k-1=0

Alik [6]

Answer:

(See explanation for further details)

Step-by-step explanation:

The real expression is:

$(k^{2}-1)\cdot x{{2} - 2\cdot k \cdot x - 3\cdot k + 1 = 0$

The general equation for the second-order polynomial is:

$x = \frac{2\cdot k \pm \sqrt{4\cdot k^{2}-4\cdot (k^{2}-1)\cdot (-3\cdot k + 1)}}{k^{2}-1}$

This condition must be observed for the case of a quadratic equation with equal roots:

$4\cdot k^{2} - 4\cdot (k^{2}-1)\cdot (-3\cdot k + 1) = 0$

$k^{2} + (k^{2}-1)\cdot (3\cdot k + 1) = 0$

$k^{2} + 3\cdot k^{3} - 3\cdot k - k^{2}-1 = 0$

$3\cdot k^{3} - 3\cdot k - 1 = 0$

7 0

3 years ago

Which of the following options is the inverse of an exponential function?

MrMuchimi

Logarithmic function

6 0

3 years ago

Read 2 more answers

How do I find the slope of a line from a table graph

Nataly_w [17]

Step-by-step explanation:

slope is the rise over run

rise= X

run= Y

X/Y = slope

6 0

3 years ago