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Brums [2.3K]
3 years ago
11

The school uses between 300 and 400 sheets of paper per school day. If paper costs the school $2.00 per 100 sheets, approximatel

y how much does the school pay for paper every month? (Remember to only count school days!) A. $140.00 B. $190.00 C. $170.00 D. $90.00
Mathematics
1 answer:
Nady [450]3 years ago
7 0

Answer:

  • Option A. $140.00

Explanation:

<u>1. Using the minimun number of sheets  of paper in the interval [300, 400]</u>

a) Cost: $ 2.00 / 100 sheets

b) 300 sheets / day × $ 2.00 / 100 sheets = $ 6.00 / day

c) Approimately 20 school days per month:

  • $ 6.00 / day × 20 day = $ 120.00

<u>2. Using the maximum number of sheets of paper in the interval [300, 400]</u>

a) Cost: $ 2.00 / 100 sheets

b) 400 sheets / day × $ 2.00 / 100 sheets = $ 8.00 / day

c) Approimately 20 school days per month:

  • $8.00 / day × 20 day = $ 160.00

<u>3. Middle value:</u>

Calculate the middle value between $160.00 and $120.00

  • [$120.00 + $160.00] / 2 = $140.00

Thus, the answer is the option A.

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frutty [35]

Answer:

The correct answer is - A)8% B) 3%

Step-by-step explanation:

A) Let assume:

the cost price of the goods - $y.

the selling price of the goods - $x.

Given: The retailer sold at 4% discount, or 0.96x (100% - 4% = 96%). Since the goods were sold to make 20% profit, therefore it was sold for:

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Solution:

The refrigerator was sold at 13% VAT at Rs. 10848:

then,

=> 1.2y + 13%(1.2y) = 10848

=> 1.2y + 0.156y = 10848

=> 1.356y = 10848

=> y = 8000

Thus, the cp is Rs 8000.

The selling price is:

=> 0.96x = 1.2y

=> 0.96x = 1.2(8000)

=> x = 10000

The sp is Rs. 10000

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(1 - discount)10000 = 9200

1 - discount = 0.92

Discount = 1 - 0.92 = 0.08 or 8%

B) Let C & M as cost price & marked price of the scanner machine respectively.  

(1 + 20/100)*C = 41400

or (6/5)*C = 41400

or C = (5/6)*41400

= 34500 (Rs)

(1 - 10/100)*(1 + 15/100)*M = 41400

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or M = (10/9)*(20/23)*41400

= 40000 (Rs)

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= (1 + 20/100 + 4/100)*C

or (9/10 + R/100)*(23/20)*40000

= (31/25)*34500

or 9/10 + R/100

= (20/23)(31/25)*(345/400)

or R/100 = 0.93 - 0.9 = 0.03

or R = 3%

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