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Svet_ta [14]
3 years ago
9

If in an equation the variables cancel out while solving and u are left with a true statement how many solutions are there and i

f in an false statement
Mathematics
2 answers:
fomenos3 years ago
8 0
Infinity and many more beyond
Deffense [45]3 years ago
4 0

Answer: infinitely many and none

Step-by-step explanation:

if all variables cancel and you are left with zero, there are infinitely many solutions. if it is false there are no solutions.

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Jared surfed for 1/3 of the 9 hours he was at the beach. he spent the rest of the time building a castle. how many hours did he
Archy [21]
He spent 6hrs at the beach
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A bag contains 1 yellow ball and 9 red balls . A ball is chosen at random from the bag . what is the best answer for the probabi
Strike441 [17]
Your answer is unlikely. That would be a 1 out of 10 chance.
6 0
3 years ago
in 2005, the total waste generated in a certain country was 3.474x10^9 pounds. also in 2005, the countrys population was 1.23x10
Serggg [28]

Answer:

2824

Step-by-step explanation:

Take the number of pounds and divide by the number of people:

3.474×10⁹ / 1.23×10⁶

Divide the coefficients and subtract the exponents:

(3.474 / 1.23) × 10⁹⁻⁶

2.824×10³

So the country produced about 2,824 pounds of garbage per person in 2005.

7 0
3 years ago
Find the discrimnate of -x^2+2x-8=0
Lisa [10]

Answer:

-28

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Let X denote the temperature (degree C) and let Y denote thetime in minutes that it takes for the diesel engine on anautomobile
BlackZzzverrR [31]

Answer:

Step-by-step explanation:

Given f_{XY} (x,y) = c(4x + 2y +1) ; 0 < x < 40\,and\, 0 < y

a)

we know that \int\limits^\infty_{-\infty}\int\limits^\infty_{-\infty} {f(x,y)} \, dxdy=1

therefore \int\limits^{40}_{-0}\int\limits^2_{0} {c(4x+2y+1)} \, dxdy=1

on integrating we get

c=(1/6640)

b)

P(X>20, Y>=1)=\int\limits^{40}_{20}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy

on doing the integration we get

                        =0.37349

c)

marginal density of X is

f(x)=\int\limits^2_{0} {\frca{1}{6640}(4x+2y+1)} \, dy

on doing integration we get

f(x)=(4x+3)/3320 ; 0<x<40

marginal density of Y is

f(y)=\int\limits^{40}_{0} {\frca{1}{6640}(4x+2y+1)} \, dx

on doing integration we get

f(y)=\frac{(y+40.5)}{83}

d)

P(01)=\int\limits^{40}_{0}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy

solve the above integration we get the answer

e)

P(X>20, 0

solve the above integration we get the answer

f)

Two variables are said to be independent if there jointprobability density function is equal to the product of theirmarginal density functions.

we know f(x,y)

In the (c) bit we got f(x) and f(y)

f(x,y)cramster-equation-2006112927536330036287f(x).f(y)

therefore X and Y are not independent

4 0
3 years ago
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