Question

ANSWER CORRECTLY AND I WILL PUT YOU THE BRAINLIEST! (SEE ATTACHMENT BELOW)

Answer 1

the inverse of a two-by-two matrix

A=$\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]$

whose inverse is

$A^{-1}=\frac{\left[\begin{array}{ccc}d&-b\\-c&a\end{array}\right]}{ad-bc}$

Substituting values, we get

$A^{-1}=\frac{\left[\begin{array}{ccc}7&9\\-8&-5\end{array}\right]}{37}$

which is not the same as matrix B. Therefore B is not the inverse of A.

We can prove similarly that A is not the inverse of B.