Answer:
In quadrilateral ABCD we have
AC = AD
and AB being the bisector of ∠A.
Now, in ΔABC and ΔABD,
AC = AD
[Given]
AB = AB
[Common]
∠CAB = ∠DAB [∴ AB bisects ∠CAD]
∴ Using SAS criteria, we have
ΔABC ≌ ΔABD.
∴ Corresponding parts of congruent triangles (c.p.c.t) are equal.
∴ BC = BD.
Answer:
<em>H</em>₀: <em>μ₁ = μ₂= μ₃</em>
<em>Hₐ: </em>At least one of the means is different.
Step-by-step explanation:
Analysis of variance or ANOVA test is used to determine whether the means of different groups are similar or not.
The hypothesis of an ANOVA test for <em>n</em> homogeneous groups is:

In this case the researcher is testing whether the mean bone mineral density is different for the three different groups.
The hypothesis for this test can be defined as follows:
<em>H</em>₀: The mean bone mineral density is not different for the three different groups, i.e. <em>μ₁ = μ₂= μ₃</em>
<em>Hₐ: </em>The mean bone mineral density is different for the three different groups, i.e. at least one of the means is different.
Answer:
a. 14 b. -2
Step-by-step explanation:
a. 10=2x-18
28=2x ; x=14
b. 3x+12=2x+6+4
3x+12=2x+10
x=-2