Solution:
Let
X = height of Cody on the first day of school last year
Given:
Y= height of Cody on the first day of school year = 165 cm
10%(X)+X=Y
.10(X)+X=165
1.10X=165
X=165/1.1
<span>X=
150 cm = height of Cody on the first day of school last year</span>
Use the FOIL method: First, Outside, Inside, Last
3x(2x) = 6x²
3x(-4) = -12x
3(2x) = 6x
3(-4) = -12
6x² -12x + 6x-12
Combine like terms
-12x + 6x = -6x
6x² - 6x - 12 is your answer
hope this helps
STEP - BY - STEP EXPLANATION
Given:
Step 1
Suppose x= -3, then
x+ 3
Step 2
Divide the polynomial by (x+ 3)
Step 3
Determine the remainder and quotient from the above.
Quotient = x²+ x - 3
Remainder = 13
ANSWER
Quotient = x²+ x - 3
Remainder = 13
Answer:
Range = {3, -1, 15}
Step-by-step explanation:
Domain = {0,2,-6}
function : y= -2x + 3
We replace the value of x with domain,
when x = 0
y = -2 × 0 + 3
y = 3
When x = 2
y = -2 × 2 + 3
y = -1
When x = -6
y = -2 × -6 + 3
y= 12 + 3
y = 15
The space between the two spheres will be the volume of the larger sphere minus the volume of the smaller sphere. Given that the volume of any sphere is:
V=(4πr^3)/3 The space between to sphere of different radius and positioned about the same center is:
S=(4πR^3)/3-(4πr^3)/3 I used S=volume of space, R=larger radius and r=smaller radius...
S=(4π/3)(R^3-r^3), we are told that R=5 and r=4 so
S=(4π/3)(5^3-4^3)
S=(4π/3)(125-64)
S=(4π/3)(61)
S=244π/61
S=4π cm^3
S≈12.57 cm^3 (to nearest hundredth of a ml)
