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3 years ago

If x to the power of 2 = 10 what is the value of x?

Mathematics

2 answers:

serg [7]3 years ago

7 0

X squared is equal to 10

Darya [45]3 years ago

5 0

Answer:

x² = 10

x = ±√10 (Take the square root of both sides)

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Can you help me please

notsponge [240]

9514 1404 393

Answer:

reflection across the origin
rotation 180° about the origin
reflection across the x-axis, and translation right 6 units

Step-by-step explanation:

The figure and its image are symmetrical about the origin, so the following three transformations are equivalent:

1. reflection across the origin

2. rotation 180° about the origin

3. reflection across both x- and y-axes, in either order

The figure itself has left-right symmetry, so only one reflection is necessary to map the figure to its image: reflection across a horizontal line. Following that reflection, the image can be put into place by an appropriate translation. One such pair of transformations is ...

4. reflection across the x-axis and translation 6 units right, in either order

8 0

2 years ago

The cosine of 23° is equivalent to the sine of what angle

Archy [21]

Answer:

So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).

(There are more values since we can go around the circle from 67 degrees numerous times.)

Step-by-step explanation:

You can use a co-function identity.

The co-function of sine is cosine just like the co-function of cosine is sine.

Notice that cosine is co-(sine).

Anyways co-functions have this identity:

$\cos(90^\circ-x)=\sin(x)$

$\sin(90^\circ-x)=\cos(x)$

You can prove those drawing a right triangle.

I drew a triangle in my picture just so I can have something to reference proving both of the identities I just wrote:

The sum of the angles is 180.

So 90+x+(missing angle)=180.

Let's solve for the missing angle.

Subtract 90 on both sides:

x+(missing angle)=90

Subtract x on both sides:

(missing angle)=90-x.

So the missing angle has measurement (90-x).

So cos(90-x)=a/c

and sin(x)=a/c.

Since cos(90-x) and sin(x) have the same value of a/c, then one can conclude that cos(90-x)=sin(x).

We can do this also for cos(x) and sin(90-x).

cos(x)=b/c

sin(90-x)=b/c

This means sin(90-x)=cos(x).

So back to the problem:

cos(23)=sin(90-23)

cos(23)=sin(67)

So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).

6 0

2 years ago

HELP ME PLS

mina [271]

Age>8. I think ..............

7 0

2 years ago

Read 2 more answers

What is the approximate distance between points A and B?

Aleks04 [339]

Answer:

$\displaystyle d \approx 7.62$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Find points from graph.

Point A(1, 4)

Point B(-2, -3)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [DF]: $\displaystyle d = \sqrt{(-2-1)^2+(-3-4)^2}$
(Parenthesis) Subtract: $\displaystyle d = \sqrt{(-3)^2+(-7)^2}$
[√Radical] Exponents: $\displaystyle d = \sqrt{9+49}$
[√Radical] Add: $\displaystyle d = \sqrt{58}$
[√Radical] Evaluate: $d = 7.61577$
Round: $\displaystyle d \approx 7.62$

3 0

2 years ago

What is the following product

dangina [55]

Option B is correct.

Step-by-step explanation:

We need to solve: $\sqrt[3]{x^2}\sqrt[4]{x^3}$

We know that: $\sqrt[n]{x}\sqrt[b]{x} =\sqrt[n*b]{x.x}= \sqrt[n*b]{x^2}$

Applying the above rule:

$\sqrt[3]{x^2}\sqrt[4]{x^3}\\=\sqrt[3*4]{x^2.x^3}\\=\sqrt[12]{x^5}$

So, Option B is correct.

Keywords: Solving with Exponents

Learn more about Solving with Exponents at:

#learnwithBrainly

3 0

3 years ago