Answer:
The perimeter of a parallelogram is 30cm.
Step-by-step explanation:
From the question , the given area of a parallelogram is 36 cm².
But the area of a parallelogram can be calculated using below formula
Area = base * height
From the question the distances that exist between the point of intersection of the diagonals and the sides are 2cm and 3cm respectively
There is the same distance between point of intersection of the diagonals and the opposite sides then,
The base of the side with 4cm can be calculated as
ha= 2+ 2= 4cm
But area can be calculated as A= base × height
36= b1 × h1
36=b1 × 4
b1= 9cm
The base of the other side can be calculated with 6cm height
h2= 3+3=6cm
A= b2× h2
36= b2 ×h2
36= b2× 6
b2= 6cm
Then the perimeter of the parallelogram can be calculated as
P= 2(b1 + b2)
= 2(6+9)
= 30cm
Hence,the perimeter of the parallelogram is 30cm
∠1 and ∠3 complementary,
∠1 = ∠2,
so
∠1 and ∠2 complementary.
Answer : C.
Answer:
The amount that came is 
Step-by-step explanation:
The computation is shown below:
According to the question, it is mentioned that
Multiply 4 by 
First open the equation in a fraction it would be 
Now multiplied the above fraction by a 4
That gives the result of 
Hence, the amount that came is 
We simply multiply the 4 with the given fraction
Thus the above represents the simplest form of the fraction
Answer:
Ok hi
Step-by-step explanation:
There are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned from 14 volunteers.
Given that a school dance committee has 14 volunteers and each dance requires 3 volunteers at the door, 5 volunteers on the floor and 6 on floaters.
We are required to find the number of ways in which the volunteers can be assigned.
Combinations means finding the ways in which the things can be choosed to make a new thing or to do something else.
n
=n!/r!(n-r)!
Number of ways in which the volunteers can be assigned is equal to the following:
Since 2 have not been assigned so left over volunteers are 14-2=12 volunteers.
Number of ways =14
=14!/12!(14-12)!
=14!/12!*2!
=14*13/2*1
=91 ways
Hence there are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned.
Learn more about combinations at brainly.com/question/11732255
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