First of all we need to find a representation of C, so this is shown in the figure below.
So the integral we need to compute is this:

So, as shown in the figure, C = C1 + C2, so:
Computing first integral:
Applying derivative:

Substituting this value into

Computing second integral:
Applying derivative:

Substituting this differential into


We need to know the limits of our integral, so given that the variable we are using in this integral is x, then the limits are the x coordinates of the extreme points of the straight line C2, so:
![I_{2}= -8\int_{4}^{8}}dx=-8[x]\right|_4 ^{8}=-8(8-4) \rightarrow \boxed{I_{2}=-32}](https://tex.z-dn.net/?f=I_%7B2%7D%3D%20-8%5Cint_%7B4%7D%5E%7B8%7D%7Ddx%3D-8%5Bx%5D%5Cright%7C_4%20%5E%7B8%7D%3D-8%288-4%29%20%5Crightarrow%20%5Cboxed%7BI_%7B2%7D%3D-32%7D)
Finally:
Answer:
Oils
Step-by-step explanation:
:)
You need to show us what the triangle is
Answer:
11200 for 7 engines for a total of 80 hours
Step-by-step explanation:
You have 8 engines burning 12000 .for 10 hours.
Divide 10 hours into 12000=1200 PER hour.
1200 ÷8 engines = 140 per hour per engine.
140 × # of hours (12)=1680 for 12 hours per engine.
# of engines × 1680 for 12 hour/per engine
5×1680 = 8400 of fuel for 12 hours/5 engine
Then you have 2 that runs 10 hours
2 × 140 per hour per engine =280 × 10 =2800 for 2 engines for 10 hours
8400. + 2800= 11200 of fuel for 6 engines