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Anit [1.1K]
3 years ago
6

Please help! Will mark brainliest. The answer is 1.96 but I need to know to they got the answer.

Mathematics
1 answer:
nadya68 [22]3 years ago
3 0

Here we are looking to find the critical value Z.

When alpha is 0.05:

0.05/2=.025

Using your z chart this would equal 1.96 positive or negative. Hope this helps!

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a library has 67,982 books. the children's section represents 1/3 of the total books. of the remaining books, 75% are fiction. h
ivolga24 [154]

Answer:

11331 non fiction books

Step-by-step explanation:

Given :

Total books = 67982

Childrens section = 1/3 of total

Number of children's books :

(1/3 * 67982) = 22660 books (approximately)

Books left :

67982 - 22660 = 45,322 books

Fiction books:

75% of remaining

0.75 * 45322

33991.5

= 33991 books

If the only section left is non - fiction, then

Non - fiction books = (45322 - 33991) = 11331

6 0
3 years ago
Can you please help me? I don't get it
tiny-mole [99]

.6\sqrt{36}\\.6* \sqrt{36}\\.6*6\\3.6

The answer is 3.6.

5 0
3 years ago
Read 2 more answers
How to find percent increases
Alexxx [7]
To increase a  umber by a certain percent, you imagine 100% as 1 then if you want to increase by x% you times your original number by (1+x) e.g. increase 25 by 13% 

x=13
25 × 1.13 = 28.25
6 0
3 years ago
Eight rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other ro
Brums [2.3K]

Answer:

9.11*10^-4 %

Step-by-step explanation:

To find the probability, you simply need to find the possible outcomes that allows no rooks to be in danger, and the possible amount of ways to place the rooks.

For the first outcome, you start by putting 1 rook in the first columns, you have 8 possible rows to do this. The next rook in the next column will only have 7 possible rows, as you have to exclude the one where the previous rook is located. The next rook, 6 possibilities, the next 5, and so on. So we conclude that the total amount of ways so that none of the rooks can capture any of the other rooks is 8*7*6*5*4*3*2*1 = 8! = 40320

In order to find the total amount of ways to place the rooks, you can just use a combinatoric:

\left[\begin{array}{ccc}64\\8\end{array}\right]= \frac{64!}{8!(64-8)!} = 4.43*10^9

Then:

P = \frac{40320}{4.43*10^9}*100\%=9.11*10^{-4}\%

5 0
4 years ago
Prove the following statement by contradiction using an indirect proof. In a triangle angle A = 90°, then the triangle is a righ
kati45 [8]

Answer:

I prefer taking B

Step-by-step explanation : because when the degree is 90 than it should be a right triangle

3 0
4 years ago
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