Answer: d) Not in Col in Nul A
Step-by-step explanation: The definition of <u>Column</u> <u>Space</u> of an <em>m x n</em> matrix A is the set of all possible combinations of the columns of A. It is denoted by col A. To determine if a vector is a column space, solve the matrix equation:
A.x = b or, in this case,
.
To solve, first write the augmented matrix of the system:
![\left[\begin{array}{cccc}1&0&3&-4\\-2&-1&-4&-5\\3&-3&0&3\\-1&3&6&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%263%26-4%5C%5C-2%26-1%26-4%26-5%5C%5C3%26-3%260%263%5C%5C-1%263%266%261%5Cend%7Barray%7D%5Cright%5D)
Now, find the row-echelon form of matrix A:
1) Multiply 1st row by 2 and add 2nd row;
2) Multiply 1st row by -3 and add 3rd row;
3) MUltiply 1st row by 1 and add 4th row;
4) MUltiply 2nd row by -1;
5) Multiply 2nd row by 3 and add 3rd row;
6) Multiply 2nd row by -3 and add 4th row;
7) Divide 3rd row by -15;
8) Multiply 3rd row by -15 and add 4th row;
The echelon form matrix will be:
![\left[\begin{array}{cccc}1&0&3&-4\\0&1&-2&13\\0&0&1&-\frac{51}{15}\\0&0&0&-13 \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%263%26-4%5C%5C0%261%26-2%2613%5C%5C0%260%261%26-%5Cfrac%7B51%7D%7B15%7D%5C%5C0%260%260%26-13%20%5Cend%7Barray%7D%5Cright%5D)
Which gives a system with impossible solutions.
But if
, there would be a solution.
<u>Null</u> <u>Space</u> of an <em>m x n</em> matrix is a set of all solutions to
, so vector u is a null space of A, denoted by null (A)