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3 years ago

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Answer pls? Bias matching??

1 answer:

grin007 [14]3 years ago

4 0

It’s just this because it’s that you what that mean because it is

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How to solve for slope? (pre algebra)

STALIN [3.7K]

Answer:

Ok! When given points, to find the slope, you would use this equation: y2-y1/x2-x1. Let me demonstrate. In this set to find the slope with the coordinates (10,8) and (14,20), the y2 value is 20, and the y1 value is 8, and the x2 value is 14, and the y1 value is 10. So, your equation would look like this: (20-8)/(14-10), which simplifies to 12/4, or 3! So the slope is three, and that's how you do that when using an equation. OR, you could graph them, but that isn't too reliable so I do not recommend trying it, since you may not create the right slope.

4 0

2 years ago

Below are survival times (in days) of 13 guinea pigs that were injected with a bacterial infection in a medical study:

tresset_1 [31]

Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

The dataset is given as:

91 83 84 79 91 93 95 97 97 120 101 105 98

Sort the dataset in ascending order

79 83 84 91 91 93 95 97 97 98 101 105 120

<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

$Q1 = \frac{N +1}{4}th$

So, we have:

$Q1 = \frac{13 +1}{4}th$

$Q1 = \frac{14}{4}th$

$Q1 = 3.5th$

This is the average of the 3rd and the 4th element

$Q1 = \frac{1}{2} \times (84 + 91)$

$Q1 = 87.5$

<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

$Q3 = 3 \times \frac{N +1}{4}th$

So, we have:

$Q3 = 3 \times \frac{13 +1}{4}th$

$Q3 = 3 \times 3.5th$

$Q3 = 10.5th$

This is the average of the 10th and the 11th element.

$Q_3 =\frac12 \times (98 + 101)$

$Q_3 =99.5$

<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

$IQR = Q_3 -Q_1$

$IQR = 99.5 - 87.5$

$IQR = 12$

Also, we have:

$IQR(1.5) = 12 \times 1.5$

$IQR(1.5) = 18$

<h3>The outlier range</h3>

The lower and the upper outlier range are calculated as follows:

$Lower = Q_1 - IQR(1.5)$

$Lower = 87.5- 18$

$Lower = 69.5$

$Upper = Q_3 + IQR(1.5)$

$Upper = 99.5 + 18$

$Upper = 117.5$

120 is greater than 117.5.

Hence, the dataset has an outlier and the outlier is 120

Read more about outliers at:

brainly.com/question/9933184

6 0

2 years ago

Find the mean, median and range of the following list of values and choose the correct result.

nevsk [136]

Answer:

The mean or average is 9.5 for this set of data. The median is 10.5 and the range is 5.

4 0

3 years ago

Read 2 more answers

On which number line are −4 and its opposite shown?

Natasha2012 [34]

Answer:

it is D because it is asking for the opposite of -4 so it would be the tick mark on -4 and 4

Step-by-step explanation:

5 0

2 years ago

1. Calculate the approximate area of the sector with a central angle of 87 as shown below. Round to the nearest hundredths

Nookie1986 [14]

Try b I think not sure

6 0

2 years ago