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ipn [44]
3 years ago
8

A city planner wants to build a road perpendicular to D Street. What is the slope of the new road?

Mathematics
2 answers:
Shtirlitz [24]3 years ago
8 0

Answer:

<h2>The slope of the new road is zero.</h2>

Step-by-step explanation:

According to the image attached, D street is represents by a vertical line, which angle of inclination is 90°. In other words, the slope of D street is infinite.

So, if the new road is going to be perpendicular to D street, that means the new road has 0° of inclination, because if they are perpendicular and D street is vertical, that means the new road is horizontal, which have 0° of inclination.

Now, the slope of an horizontal line is zero.

Therefore, the slope of the new road is zero.

Romashka-Z-Leto [24]3 years ago
7 0

Answer:

The slope of the new road is 0.

Step-by-step explanation:

  • the slope of d street line is tan(90)

[if the angle made by a line with x axis is \alpha then, the slope of that line will be tan(\alpha) ]

  • here, the angle made by the d street line with x axis is 90 degrees.
  • if a road is to be built which is perpendicular to d street , it should make 0 degrees i.e, it should be parallel to x axis .
  • so, the slope of new road will be tan(0) = 0
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Shtirlitz [24]
For this case, the first thing we are going to do is rewrite the equation correctly.
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Strike441 [17]

The value of the angle m∠4 is 105 degrees.

<h3>How to find angles in a quadrilateral?</h3>

The sum of angles in a quadrilateral is 360 degrees.

Therefore,

m∠1 + m∠2  + m∠3 + m∠4 = 360°

Hence,

x + x + 10 + x + 20 + x + 30 = 360

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learn more on quadrilaterals here: brainly.com/question/17178852

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babymother [125]

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Step-by-step explanation:

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laila [671]

Answer:

The value of angle is 56.9°

Step-by-step explanation:

First, you have to find the length of hypotenuse using Pythagoras' Theorem, c² = a² + b² :

{c}^{2}  =  {a}^{2}  +  {b}^{2}

let \: a = 8.25 \\ let \: b = 6.45

{c}^{2}  =  {8.25}^{2}  +  {6.45}^{2}

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In order to find θ, you have to apply Sine Rule :

\sin(θ)  =  \frac{opposite}{adjacent}

let \: oppo. = 8.77 \\ let \: hypo. = 10.47

\sin(θ)  =  \frac{8.77}{10.47}

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θ = 56.9 \: (1d.p)

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