Square meters. Centimeters would be too small, meters measure one dimension, and cubic meters measure three dimensions. We need to measure two dimensions, so we use square meters.
Answer:
y = -4x + 10
Step-by-step explanation:
I am going to assume you are trying to write the equation of a line.
4x + y = 10
4x - 4x + y = 10 - 4x
y = -4x + 10
P=24=6×6=36
P=26=9×4=36
P=33=?
P=38=?
(not sure on last two)
Answer: ![x=45](https://tex.z-dn.net/?f=x%3D45)
<u>Simplify both sides of the equation</u>
<u></u>![x+1.2x+1=100](https://tex.z-dn.net/?f=x%2B1.2x%2B1%3D100)
(Combine Like Terms)
![2.2x+1=100](https://tex.z-dn.net/?f=2.2x%2B1%3D100)
<u>Subtract 1 from both sides</u>
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<u>Divide both sides by 2.2</u>
<u></u>
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Answers:
- x = 7
- Area of shaded region = 162 square units
You may need to leave off the "square units" portion.
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Explanation:
For now, ignore the smaller rectangle and its dimensions. The larger rectangle has sides 3x and x+5, which I'll call the length and width.
L = 3x
W = x+5
The perimeter of any rectangle is P = 2(L+W). Plug in those values of L and W, and also the given perimeter P = 66. Isolate x.
P = 2(L+W)
2(L+W) = P
2(3x+x+5) = 66
2(4x+5) = 66
8x+10 = 66
8x = 66-10
8x = 56
x = 56/8
x = 7
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Now that we know x, we can find the area of the rectangles.
As you probably can guess, the shaded region is the difference of the two areas.
A = area of larger rectangle
A = (length)*(width)
A = (3x)*(x+5)
A = (3*7)*(7+5)
A = 252
B = area of smaller rectangle
B = (x+3)*(x+2)
B = (7+3)*(7+2)
B = 90
C = area of shaded region
C = A - B
C = 252 - 90
C = 162 square units is the area of the shaded region.