<h2>
Answer with explanation:</h2>
We are asked to prove by the method of mathematical induction that:
where n is a positive integer.
then we have:
Hence, the result is true for n=1.
- Let us assume that the result is true for n=k
i.e.
- Now, we have to prove the result for n=k+1
i.e.
<u>To prove:</u> 
Let us take n=k+1
Hence, we have:
( Since, the result was true for n=k )
Hence, we have:
Also, we know that:
(
Since, for n=k+1 being a positive integer we have:
)
Hence, we have finally,
Hence, the result holds true for n=k+1
Hence, we may infer that the result is true for all n belonging to positive integer.
i.e.
where n is a positive integer.
Answer:
x=1/3 or x=−2
if i can be brainliest that would be great
Step-by-step explanation:
Step 1: Add 2 to both sides.
3x^2+5x−2+2=0+2
3x^2+5x=2
Step 2: Since the coefficient of 3x^2 is 3, divide both sides by 3.
3x^2+5x/3=2/3
x^2+5/3x=2/3
Step 3: The coefficient of 5/3x is 5/3. Let b=5/3.
Then we need to add (b/2)^2=25/36 to both sides to complete the square.
Add 25/36 to both sides.
x^2+5/3x+25/36=2/3+25/36
x^2+5/3x+25/36=49/36
Step 4: Factor left side.
(x+5/6)^2=49/36
Step 5: Take square root.
x+5/6=±√49/36
Step 6: Add (-5)/6 to both sides.
x+5/6+ −5/6=
−5/6±√49/36x=−5/6±√49/36x=
1/3 or x=−2
Answer:
9 + 2j is the required algebraic equation.
I think it’s 57 bc it is a 90* angle and a 33 so that minus 180
