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Alja [10]
3 years ago
6

F(x)=−4x−9 when x=−5.

Mathematics
2 answers:
KengaRu [80]3 years ago
8 0

Answer:

11

Step-by-step explanation:

x=-5

-4(-5)-9

=20-9

=11

Hope this helps, and marking me as a brainliest would help me too;)

KengaRu [80]3 years ago
7 0

Answer:

11

Step-by-step explanation:

We just have to plug in -5 for x and when we do so we get f(-5) = -4 * (-5) - 9 = 20 - 9 = 11.

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Step-by-step explanation:

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What is the value of b? 1/3 (2b +9)= 2/3 [b+9/2]
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b=-4,5
6 0
4 years ago
Answer this and ill give you all my points if you answer them all.
sertanlavr [38]

Answer: its not clear

Step-by-step explanation:

7 0
3 years ago
Which functons have graphs that are less steep than the graph of f(x)=2x^2
adell [148]
The answers are D and E, I took this quiz as well
3 0
4 years ago
Read 2 more answers
Part A: Explain why the x-coordinates of the points where the graphs of the equations
Furkat [3]

A. Answer: It is a system of equations that can be solved using substitution method; x = -3

<u>Step-by-step explanation:</u>

y = 4⁻ˣ

y = 8⁻ˣ⁻¹

Use substitution to replace y in the second equation with 4⁻ˣ

4⁻ˣ = 8⁻ˣ⁻¹

Solve by manipulating the 4 and 8 so they have the same base, then set the exponents equal to each other and solve for x

2²⁽⁻ˣ⁾ = 2³⁽⁻ˣ⁻¹⁾

2(-x) = 3(-x - 1)

-2x = -3x - 3

  x = -3

Plug the x-value into either of the equations to solve for y

y = 4⁻ˣ

y = 4⁻⁽⁻³⁾

y = 4³

y = 64

Solution is: (-3, 64)

********************************************************************************************

B.

\begin{array}{c||c}\ \quad \underline{y=4^{-x}\quad} \ &\quad \underline{y=8^{-x-1}}\quad \\\end{array}\\\begin {array}{c|c||c|c}\quad \underline{x} \quad&\quad \underline{y} \quad &\quad \underline{x} \quad&\quad \underline{y} \quad \\ -3&64&-3&64\\&&&\\-2&16&-2&8\\&&&\\-1&4&-1&1\\&&&\\0&1&0&\dfrac{1}{8}\\ &&&\\1&\dfrac{1}{4}&1&\dfrac{1}{64}\\&&&\\2&\dfrac{1}{16}&2&\dfrac{1}{512}\\&&&\\3&\dfrac{1}{64}&3&\dfrac{1}{4096}\\\end{array}

Notice that they share the same x, y-coordinate: (-3, 64)

*******************************************************************************************

C. Answer: Graph both equations to see where they cross

<u>Step-by-step explanation:</u>

see attached graph

4 0
4 years ago
Read 2 more answers
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