<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B4a%20%7B%7D%5E%7B6%7D%20%7D%20%20%5C%3A%20%20%2B%20%20%5Cfrac%7B2%7D%7Ba%2

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3 years ago

0%7B%7D%5E%7B%20-%203%7D%20%7D%20%20%5C%3A%20%20-%20%28a%20%7B%7D%5E%7B2%7D%20%29%20%5C%3A%20%20%5Cfrac%7B3%7D%7B2%7D%20" id="TexFormula1" title=" \sqrt[3]{4a {}^{6} } \: + \frac{2}{a {}^{ - 3} } \: - (a {}^{2} ) \: \frac{3}{2} " alt=" \sqrt[3]{4a {}^{6} } \: + \frac{2}{a {}^{ - 3} } \: - (a {}^{2} ) \: \frac{3}{2} " align="absmiddle" class="latex-formula">
evaluate step by step

Mathematics

1 answer:

Mumz [18]3 years ago

8 0

I'm not sure about my answer,but still writing it...

= ³√4a⁶ - 2/a-³ - (a²)3/2

= a² × ³√4 - 2a³ - 3a²/2

Cann't think that it could be futher more evaluted

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The two legs of right triangle measures 6 and 8 inches respectively. What is the area of the circle that contains all 3 vertical

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Answer:

See image.

Step-by-step explanation:

Remember if you have a right angle inside of a circle, the hypotenuse is going to land exactly on the diameter. Also, Area of a circle = (pi)r^2 Lastly, remember pythagorean triples such as 3,4,5 or at least, the Pythagorean theorem a^2 + b^2 = c^2