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Yanka [14]
3 years ago
5

Mr.Thompson took his 5 children to the bowling alley. The cost for children 12 and older is $3.50. The cost for children under 1

2 is $2.25 . He spends a total of $16.25. How many of his children are 12 and older
Mathematics
2 answers:
telo118 [61]3 years ago
4 0
16.25$ my bro..........................
nikklg [1K]3 years ago
3 0
4 of his children are 12 and older
$3.50 x 4 would be 14 dollars.
14+ $2.25= $16.25
 hope this helps!
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Between 20 and 28 students signed up for the chess club. The students could not be divided exactly into groups of 2,3,4 or 5. Ho
Artemon [7]
23

Those are not the answer: 
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2) 21 - can be divided by 3
3) 22 - can be divided by 2
4) 24 - can be divided by 2 and 4.
5) 25 - can be divided by 5
6) 26 - can be divided by 2
7) 27 - can be divided by 3
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8 0
3 years ago
Solve 4/7- (-4/7)<br>A. 8/7<br>B.-8/7<br>C.-4/7<br>D.4/7​
mart [117]

Answer:

A. 8/7

Step-by-step explanation:

<h3>Step 1     </h3>

4/7 - (-4/7) --> 4/7 + 4/7

The two minutes turn into a plus, removing the bracket.

<h3>Step 2</h3>

4/7 + 4/7 = 8/7

Add the two fractions together.

3 0
1 year ago
Read 2 more answers
cole puts 68 books in a bookcase.he puts an equal number of books on each of 9 shelves and 5 books on the last shelf. how many b
fredd [130]
9x + 5 = 68
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3 0
3 years ago
Read 2 more answers
in a given classroom the number of girls is 10 greater than number of boys if the ratio of the number of girls to the number of
Xelga [282]

Answer:

a) 35,  b) 25,  c) 60

Step-by-step explanation:

The number of girls is 10 more than the number of boys, so it's a good thing to choose a variable to represent the number of boys.

Number of boys:  b

Number of girls:  b + 10

Ratio of girls:boys is 7:5, so

\frac{b+10}{b}=\frac{7}{5}

"Cross multiply" to get

7b=5(b+10)\\7b=5b+50\\2b=50\\b=25

There are 25 boys.  There are 10 more girls, so the number of girls is 35, and the total number of students is 60.

That's a packed classroom!

8 0
3 years ago
Can someone walk me through this?
Diano4ka-milaya [45]
So you can set up proportion.

\dfrac{7.5\ \text m}{76^\circ} = \dfrac C{360^\circ}

Here, you need to solve for C.

You can do that by multiple both sides by 360 and then you should get 360^\circ\cdot\dfrac{7.5\ \text m}{76^\circ} = C \approx \boxed{35.526\ \text m}

Hope this helps.
3 0
3 years ago
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