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Murljashka [212]
3 years ago
10

Given: ∠GHD and ∠EDH are right; GH ≅ ED Triangles G H D and E D H overlap and intersect at point F. The triangles share side H D

. Sides G H and E D are congruent. angles G H D and E D H are right angles. Which relationship in the diagram is true ?
A. △GHD ≅ △EDH by SAS
B. △GHF ≅ △EDF by SSS
C. △FDH ≅ △FDE by ASA
D. △HFD ≅ △HFG by SSS
Mathematics
1 answer:
dybincka [34]3 years ago
4 0

Answer:

The answer is A

Step-by-step explanation:

I just took the testand aced it

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What is the value of the expression image÷image
umka2103 [35]

Answer:

theres no image bro

Step-by-step explanation:

8 0
3 years ago
Tennis distribution buys rackets at a wholesale price of 25$ per racket and sells them for 75.00$ each. What is the percent incr
Marrrta [24]

Answer:

200%

Step-by-step explanation:

25 would be 100 it marks them up 50 = 200 %

8 0
4 years ago
Evaluate -6 minus parentheses -1 parentheses
GREYUIT [131]
-6 minus parentheses -1 parentheses

-6 - (-1)
When there are two negatives, they cancel out to create a positive.

-6 + 1

The answer is -5.
6 0
3 years ago
The output of an economic system​ Q, subject to two​ inputs, such as labor L and capital​ K, is often modeled by the​ Cobb-Dougl
Anna35 [415]

Answer:

Step-by-step explanation:

Given

Economic system Q is given by

Q=cL^aK^b

also a+b=1

if Q=12,200

a=\frac{1}{6}

b=\frac{5}{6}

c=42

substitute these values

12,200=42\times (L)^{\frac{1}{6}}K^{\frac{5}{6}}

(L)^{\frac{1}{6}}K^{\frac{5}{6}}=\frac{12,200}{42}

K^{\frac{5}{6}}=\frac{12,200}{42(L)^{\frac{1}{6}}}

K=(\frac{12,200}{42})^{\frac{6}{5}}\times \frac{1}{L^{5}}

differentiate w.r.t to L to get \frac{dK}{dL}

\frac{dK}{dL}=(\frac{12,200}{42})^{\frac{6}{5}}\times (-5)\times L^{-6}

\frac{dK}{dL}=-5(\frac{12,200}{42})^{\frac{6}{5}}\times \frac{1}{L^6}

\frac{dK}{dL}=-\frac{4515.466}{L^6}

6 0
3 years ago
Which graph shows a set of ordered pairs that represents a function?
pychu [463]

Answer:

B represents a function.

Step-by-step explanation:

Recall these characteristics of a "function:"

Only one y-value can be associated with each x-value.  

Thus, A could not represent a function because there are two points with x = 1 and two different y-values:  (1, 1) and (1, -2).  

B represents a function because for each input (x-value) there is one and only one y-value associated.

C not a function:  (2, 3) and (2, -3) have two different y-values associated with one x-value (2).

D not a function:  (-3, 4) and (-3, -4) (see A and C, above)

6 0
3 years ago
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