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Drupady [299]
2 years ago
14

{(5,2), (-2,4), (2, -7)} Domain: Range:

Mathematics
2 answers:
Mama L [17]2 years ago
7 0

Answer:

Domain : {-2,2,5}

Range:{ -7,2,4}

Step-by-step explanation:

The domain is the inputs

Domain : {-2,2,5}

The range is the outputs

Range:{ -7,2,4}

Svetradugi [14.3K]2 years ago
5 0

Answer:

Step-by-step explanation:

The domain are all the x values in order, no repeats allowed:

D = {-2, 2, 5}

Same thing for the range, except these are the y values:

R = {-7, 2, 4}

The coordinates stated this way don't match up to what they are in coordinate form, but they don't have to.

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A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per
Tems11 [23]

Answer:

The pressure is changing at \frac{dP}{dt}=3.68

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of \frac{dV}{dt}=-4 \:{\frac{cm^3}{min}} and we want to find at what rate is the pressure changing.

The equation that model this situation is

PV^{1.4}=k

Differentiate both sides with respect to time t.

\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)

Apply this rule to our expression we get

V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0

Solve for \frac{dP}{dt}

V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}

when P = 23 kg/cm2, V = 35 cm3, and \frac{dV}{dt}=-4 \:{\frac{cm^3}{min}} this becomes

\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68

The pressure is changing at \frac{dP}{dt}=3.68.

7 0
3 years ago
Can someone help me write the equations and solve, please.
Novay_Z [31]

Answer:

Number 11: She has to add 5/36 of a cup

Number 12: The present costs $22,2

Number 13: 56,7 pounds is the weight of the package.

Number 14: You started with 40 muffins

Step-by-step explanation:

<u>Number 11</u>: 1/4 = 9/36  and 1/9 = 4/36

3*1/4  -  3*1/9  = 3*9/36  - 3*4/36  = 5/36

<u>Number 12:</u> 13,32/x= 3/5 ( or 0,6)

x = 13,32/0,6 = 22,2

<u>Number 13:</u> x * 5/7 = 40,5

x = 40,5/ (5/7) or 40,5 * 7/5 = 283,5/5 = 56,7

<u>Number 14:</u> 12/x = 3/10 (or 0,30)

x= 12/0,30 = 40

6 0
3 years ago
A recipe for one full cake calls for one fourth cup of sugarIf three eighths of a cup of sugar is used, how many cakes were made
marin [14]

Answer:

1 1/2 cakes

Step-by-step explanation:

3/8 ÷ 1/4

3/8 * 4/1

12/8

3/2

1 1/2

5 0
2 years ago
What is the slope-intercept form of the function described by this table?
Andru [333]

Answer:

<em>y = - 3x + 4 </em>

Step-by-step explanation:

m = \frac{y_{2} -y_{1} }{x_{2} -x_{1} }

y - y_{1} = m( x - x_{1} ) Point-slope form

y = mx + b  Point-intercept form

(1, 1)

(2, - 2)

m = (- 2 - 1 ) / (2 - 1) = - 3

y - 1 = - 3( x - 1 )

<em>y = - 3x + 4</em>

6 0
3 years ago
How do I solve this I'm having a problem.
Llana [10]
How do you solve what
4 0
3 years ago
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