{(5,2), (-2,4), (2, -7)} Domain: Range:
2 answers:
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Answer:
a) 0.018
b) 0
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 14.4 in
Standard Deviation, σ = 1 in
We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.
Formula:
a) P(breadth will be greater than 16.5 in)
P(x > 16.5)
Calculation the value from standard normal z table, we have,
0.018 is the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.5 in.
b) P( with 123 randomly selected men, these men have a mean hip breadth greater than 16.5 in)
Formula:
P(x > 16.5)
Calculation the value from standard normal z table, we have,
There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in
Answer: 1. 7
2. 100
3. 193.8
4. 0.8
5. 90.6
Step-by-step explanation:
1. Given the data 9,3,10,12,4,5,12,2
For finding the median we arrange it in ascending order
2,3,4,5,9, 10,12,12
Since the no of observations are even
∴ median =
=
=
=7
i.e. Median =7
2. Given the data
23, 95,100,23,100,100
Since the no 100 is repeated thrice i.e. the maximum no of times
∴ Mode=100
3.
Given the data
108, 305,252,113, 191
Mean=
=
=193.8
4. Money spent in the first week
= $11.52, $6.48, $5.99, $14.00, and $9.50
Total for the first week
=11.52+6.48+5.99+14.00+9.50
=$47.49
Now she spent $4 more in the second week
i.e.$47.49+4
=51.49$
Increase in mean =
=0.8
5.
Given
2 students scored 100 each
9 students scored 95 each
10 students scored 90 each
3 students scored 80 each
1 student scored 70
Total score of students =
=2265
The average score
=
=90.6