Answer:
<h3>Q1</h3>
<u>Use slope formula</u>
- m = (y2 - y1)/(x2 - x1)
- m = (-2 - 6)/(3 - 7) = -8 / -4 = 2
- m = 2
<h3>Q2</h3>
Angles 2 and 6 are on the corresponding sides of the parallel lines, hence are corresponding angle
<u>Correct option is </u>
<h3>Q3</h3>
Congruent triangles have congruent corresponding parts
- ΔABC ≅ Δ GHI
- AB≅GH
- AB = GH = 13
<u>Correct choice is</u>
<h3>Q4</h3>
Option b is correct for any line and doesn't make the lines parallel. The rest of the options are correct for parallel lines.
<u>Correct option is the last one:</u>
Answer:
W = - 6
Step-by-step explanation:
-3(-8w+1) - w = 5(w-1) - 1 -> (Original equation)
24w - 3 - w = 5w - 5 - 1 -> (Expanded version)
23w - 3 = 5w - 6 -> (Simplified version)
18w - 3 = - 6 -> (Subtract 5w from both sides)
18w = - 3 -> (Add 3 to both sides)
w = 18/-3 which is - 6 -> (Doing 18/-3)
Answer:
The answer is c.
Step-by-step explanation:
-5x + 5 > 160 - 10x
5x > 155
x > 31
Answer:
V≈381.7ft³
Step-by-step explanation:
try using a sphere calculator next time its a lot easier and saves time
Answer:
15 seconds.
Step-by-step explanation:
∵ The distance covered by plane in first second = 100 ft,
Also, in each succeeding second it climbs 100 feet more than it climbed during the previous second,
So, distance covered in second second = 200,
In third second = 300,
In fourth second = 400,
............, so on....
Thus, the total distance covered by plane in n seconds = 100 + 200 + 300 +400......... upto n seconds
( Sum of AP )
Suppose the distance covered in n seconds is 12,000 feet,
∵ n can not be negative,
Hence, after 15 seconds the plane will reach an altitude of 12,000 feet above its takeoff height.
