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Evgen [1.6K]
2 years ago
11

How many lines of symmetry does the middle shape have ?​

Mathematics
2 answers:
Anarel [89]2 years ago
6 0

Answer:

Three

Step-by-step explanation:

The answer is that the shape has three lines of symmetry, one from each vertex to the middle of the opposite side

alina1380 [7]2 years ago
5 0

Answer:

<h2>Three</h2>

The answer is that the shape has three lines of symmetry, one from each vertex to the middle of the opposite side.

Step-by-step explanation:

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Choose the Athat seems to be congruent to the given one.
julia-pushkina [17]

Answer:

a. ∆EGF ≅ ∆EGD

Step-by-step explanation:

Congruent triangles would have the same side lengths and the same measure of angles.

From the figure given:

EG in ∆EGF ≅ EG in ∆EGD

GF in ∆EGF ≅ GD in ∆EGD, also

EF ≅ ED.

The three angles in ∆EFG are also congruent to the three angles in ∆EGD.

Therefore, ∆EGD is congruent to ∆EGF.

∆EGF ≅ ∆EGD

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2 years ago
Given a quadratic function, y=x2+bx+c what happens to the graph when "a" is positive? A.the parabola opens down, the vertex is t
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D

Step-by-step explanation:

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3 years ago
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NISA [10]

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C. The lines are perpendicular

Step-by-step explanation:

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4 0
2 years ago
Factor 6(2p q)^2 -5(2p q) - 25
kherson [118]
Treat the 2p+q as x

6x2-5x-25
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3 0
3 years ago
A kite is being flown at a 45 angle. The string of the kite is 120 feet long. How high is the kite above the point at which the
MrRissso [65]

Answer: The height of the kite above the point at which the string is held is 120\sqrt{2} feet.

Step-by-step explanation:

Given : A kite is being flown at 45^{\circ} . The string of the kite is 120 feet long.  

Let AB denote the string of kite and AC be the height of the kite above the point at which the string is held.

Now, in right Δ ABC

\sin45^{\circ}=\frac{AC}{AB}\\\Rightarrow\ \frac{1}{\sqrt{2}}=\frac{AC}{120}\\\Rightarrow\ AC=120\sqrt{2}

hence, The height of the kite above the point at which the string is held is 120\sqrt{2} feet.

5 0
3 years ago
Read 2 more answers
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