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olganol [36]
3 years ago
14

Calculate the average (arithmetic mean)of the list of numbers shown in the table (rounded to the nearest tenth) 1049.0 1180.0 11

80.1 1348.7
Mathematics
1 answer:
horrorfan [7]3 years ago
4 0

Answer:

The average of the list of numbers is 1189.5

Step-by-step explanation:

Mean of a data-set:

The mean of a data-set is the sum of all values in the data-set divided by the number of values.

In this question:

Sum:

1049.0+1180.0+1180.1+1348.7 = 4757.8

Mean:

4 values, so:

4757.8/4 = 1189.5

The average of the list of numbers is 1189.5

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When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal. During one
Triss [41]

Answer:

0.82 = 82% probability that at least one party will not order drinks

Step-by-step explanation:

For each party, there are only two possible outcomes. Either they will order drinks with their meal, or they will not. The probability of a party ordering drinks with their meal is independent of other parties. So the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal.

This means that p = 0.75

During one hour, Ryan served 6 parties. Assuming that each party is equally likely to order drinks, what is the probability that at least one party will not order drinks?

6 parties, so n = 6.

Either all parties will order drinks, or at least one will not. The sum of the probabilities of these events is decimal 1. So

P(X = 6) + P(X < 6) = 1

We want P(X < 6). So

P(X < 6) = 1 - P(X = 6)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{6,6}.(0.75)^{6}.(0.25)^{0} = 0.18

P(X < 6) = 1 - P(X = 6) = 1 - 0.18 = 0.82

0.82 = 82% probability that at least one party will not order drinks

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