Question

Jimmy is trying to dive down and touch the bottom of the pool. On his first try he makes it 1/3 of the way to the bottom. On his second try he makes it 3/5 of the way to the bottom. Jimmys second dive was deeper than his first dive by what fraction of the pool?

Answer 1

Answer:

Jimmy's second dive was $\frac{4}{15}$ of the pool deeper than the first one

Explanation:

We are given that:

First dive was $\frac{1}{3}$ of the way to the bottom

Second dive was $\frac{3}{5}$ of the way to the bottom

We know that the second dive was deeper than the first one since $\frac{3}{5} > \frac{1}{3}$

To know how much deeper the second dive was compared to the first one, we will simply subtract the depth of the first dive from that of the second one

Therefore:

The second dive was $\frac{3}{5} - \frac{1}{3} = \frac{9}{15} - \frac{5}{15} = \frac{4}{15}$ of the pool deeper than the first one

Hope this helps :)