From the figure shown:
Given that k=89, then:
c=g=k=o=s=w=89
b=f=j=n=r=v=89
d=h=l=p=t=x=180-89=91
a=e=i=m=q=u=91
thus the sum of <span> s,e,q,u,o,i,a will be:
</span>s+e+q+u+o+i+a
=89+91+91+91+89+91+91
=633°
Answer: 633°
7/12
1/3=4/12
2/3=8/12
7/12>1/3
<span>7/12<2/3
</span>
convert all of these to a common denominator:
7/12 , 1/3 , 2/3
---
7/12 = 7/12
1/3 = 4/12
2/3 = 8/12
---
place into compound inequality:
---
(1/3=4/12) < (7/12=7/12) < (2/3=8/12)
Answer:
765 J
Step-by-step explanation:
We are given;
Mass of bucket = 30 kg
Mass of rope = 0.3 kg/m
height of building= 30 meter
Now,
work done lifting the bucket (sand and rope) to the building = work done in lifting the rope + work done in lifting the sand
Or W = W1 + W2
Work done in lifting the rope is given as,
W1 = Force x displacement
W1 = (30,0)∫(0.2x .dx)
Integrating, we have;
W1 = [0.2x²/2] at boundary of 30 and 0
W1 = 0.1(30²)
W1 = 90 J
work done in lifting the sand is given as;
W2 = (30,0)∫(F .dx)
F = mx + c
Where, c = 30 - 15 = 15
m = (30 - 15)/(30 - 0)
m = 15/30 = 0.5
So,
F = 0.5x + 15
Thus,
W2 = (30,0)∫(0.5x + 15 .dx)
Integrating, we have;
W2 = (0.5x²/2) + 15x at boundary of 30 and 0
So,
W2 = (0.5 × 30²)/2) + 15(30)
W2 = 225 + 450
W2 = 675 J
Therefore,
work done lifting the bucket (sand and rope) to the top of the building,
W = 90 + 675
W = 765 J
Answer:
144cm^3
Step-by-step explanation:
A=1/2bh = 1/2 (6)(8)
=24
v=A×H=(24)(6)
=144cm^3
Step-by-step explanation:
-3.25y < -61.75
<u>-3.25y</u><u> </u>< <u>-61.75</u><u> </u>
-3.25. -3.25
whenever an inequality is divided by a negative number the sign changes, so if the sign of the inequality is greater than( > ) it becomes less than( < ) or the other way around. In this case the <em>less</em><em> </em><em>than</em><em> </em>will be <em>greater</em><em> </em><em>than</em><em>.</em>
y > 19 , S.S= [ 20,21,22,23.....]
