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4 years ago

Find the GCF of 18 and 11.

Mathematics

2 answers:

docker41 [41]4 years ago

5 0

Answer:

GCF is 1

Step-by-step explanation:

The factors of 11 are: 1, 11

The factors of 18 are: 1, 2, 3, 6, 9, 18

Then the greatest common factor is 1

Vilka [71]4 years ago

3 0

Answer:

It is 1

Step-by-step explanation:

11 = 111

18 = 2^1 × 3^2

List of positive integer factors of 11 that divides 11 without a remainder.

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Mila [183]

Given : Anne buys 600 packets of mints.

Given : Of these 600 packets of mints, 34% are small packets and 40% are large packets.

$:\implies$ Total % of small and large packets is (34 + 40) = 74%

It means : The remaining percentage is of the medium packets of mints which were brought by Anne.

$:\implies$ % of medium packets brought by Anne : (100 - 74) = 26%

$:\implies \textsf{Number of medium packets brought by Anne : $\left(\dfrac{26}{100} \times 600\right)$}$

$:\implies \textsf{Number of medium packets brought by Anne : $\left(26 \times 6\right)$ = 156}$

Given : Ben buys 400 packets of mints.

$\textsf{Given : Of these 400 packets of mints, $\dfrac{3}{10}$ are small and $\dfrac{1}{10}$ are large}$

$\implies \textsf{Total fraction of small and large packets brought by Ben :$\left(\dfrac{3}{10} + \dfrac{1}{10}\right)$}$

It means : The remaining fraction is of the medium packets of mints which were brought by Ben.

$\implies \textsf{Fraction of medium packets brought by Ben : $\left(1 - \dfrac{3}{10} - \dfrac{1}{10}\right)$}$

$\implies \textsf{Fraction of medium packets brought by Ben : $\left(1 - \dfrac{4}{10}\right)$ = $\dfrac{6}{10}$}$

$:\implies \textsf{Number of medium packets brought by Ben : $\left(\dfrac{6}{10} \times 400\right)$}$

$:\implies \textsf{Number of medium packets brought by Anne : $\left(6 \times 40\right)$ = 240}$

Given : Chas buys 210 small packets of mints.

Given : Number of small packets : number of medium packets = 3 : 4

$\implies \mathsf{\dfrac{210}{number \ of \ medium \ packets} = \dfrac{3}{4}}$

$\implies \mathsf{Number \ of \ medium \ packets = \left(210 \times \dfrac{4}{3}\right)}$

$\implies \textsf{Number of medium packets brought by Chas = 280}$

Total number of medium packets of mints brought by these three shop keepers (Anne, Ben, Chas) are :

$:\implies$ (156 + 240 + 280)

$:\implies$ 676

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3 years ago

How to solve this problem.

andreyandreev [35.5K]

Notice the picture below

now, if the arc "x" is 48°, and the arc across the circle is also 48°, then those chords are congruent, notice the chords in red

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4 years ago

Solve for x in this equation: 3/4+|5-x| = 13/4

omeli [17]

Answer: X =5/2, 15/2 x=2.5, 7.5

Step-by-step explanation:

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