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d1i1m1o1n [39]
4 years ago
11

Im really struggling with these questions can anyone help me?

Mathematics
1 answer:
Alchen [17]4 years ago
8 0
Q1
the clothes are on 45% discount, wich mean they become 55% of their original price.

30× 55% =16.5
64×55%=35.2

the new salary is 103% of the original

10×103% = 10.3
11600×103% = 11,948

Q2:

1+0.24= 1.24
1- 0.27= 0.73

86×140%= 120.4
440×119%= 523.6
82×90% = 73.8
480× 73%= 350.4
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Solve the quadratic equation by completing the square. x2+6x+7=0 First, choose the appropriate form and fill in the blanks with
kirill [66]

Answer:

x^2+6x-4=0 x^2+6x=4 x^2+6x+9=13 (x+3)(x+3)=13 x+3=+or-(13^1/2) x=-3+or-13^1/2

Step-by-step explanation:

sry if im wrong :< if im right, can i have brainliest? have a wonderful day/night :D

5 0
3 years ago
Evaluate the expression 4(2x + 3) + 2(x + 1)-7
Svetlanka [38]
4 (2x + 3) + 2 (x + 1) - 7

8x + 12 + 2x +  2 - 7

10x + 7

10x = -7
10x/10 = -7/10

x = -7/10

hope this helps


4 0
3 years ago
PLEASE HELP ME!!!
Dovator [93]
Stairs because they can’t possibly walk up the stairs cause then they’ll fall
8 0
3 years ago
Read 2 more answers
1.What is the principal which would amount to $6 900 in 3 years at 5% simple interest per annum?Required to answer. Single choic
Jobisdone [24]

Answer:

c

Step-by-step explanation:

I just looked up the question

8 0
3 years ago
A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t
MakcuM [25]

Answer:

165.

Step-by-step explanation:

Since repetition isn't allowed, there would be 11 choices for the first donut, (11 - 1) = 10 choices for the second donut, and (11 - 2) = 9 choices for the third donut. If the order in which donuts are placed in the bag matters, there would be 11 \times 10 \times 9 unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type 3 \times 2 \times 1 = 6 times.

For example, if a bag includes donut of type x, y, and z, the count 11 \times 10 \times 9 would include the following 3 \times 2 \times 1 arrangements:

  • xyz.
  • xzy.
  • yxz.
  • yzx.
  • zxy.
  • zyx.

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count 11 \times 10 \times 9 by 3 \times 2 \times 1 = 6 to find the actual number of donut combinations:

\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of 3 objects from a set of 11 distinct objects:

\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

5 0
2 years ago
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