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bija089 [108]
3 years ago
13

Esmeralda bought 12.22 worth of 43 cent stamps and 81 cent stamps. The number of 81 cent stamps was 14 less than the number of 4

3 cent stamps. Solve the equation 0.43 s + 0.81 ( s − 14 ) = 12.22 for s, to find the number of 43 cent stamps Esmeralda bought.
Mathematics
1 answer:
xxTIMURxx [149]3 years ago
5 0

Answer:

The number of 43 cent stamps Esmeralda bought is <u>19</u>.

Step-by-step explanation:

Given:

Esmeralda bought 12.22 worth of 43 cent stamps and 81 cent stamps. The number of 81 cent stamps was 14 less than the number of 43 cent stamps.

Now, to solve the equation 0.43 s + 0.81 ( s − 14 ) = 12.22 for s and to find the number of 43 cent stamps.

Let the number of 43 cent stamps be s.

And, the number of 81 cent stamps be s-14.

So, to solve equation for s.

0.43 s + 0.81 ( s -14 ) = 12.22

0.43s+0.81s-11.34=12.22

1.24s-11.34=12.22

<em>Adding both sides by 11.34 we get:</em>

1.24s=23.56

<em>Dividing both sides by 1.24 we get:</em>

s=19.

<em>The number of 43 cent stamps = 19.</em>

Therefore, the number of 43 cent stamps Esmeralda bought is 19.

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A clock was reading the time accurately on Friday at noon. On Monday at 6pm the clock was running late by 468 seconds. On averag
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The clock was skipping 3 seconds every 30 minutes from Friday noon to Monday 6 pm.

The clock was still accurate by Friday noon. The clock was late by 468 seconds by Monday, 6 pm.

To solve the problem, we must:

Know how many 30-minutes have passed during the time period.

1 day = 24 hours

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1 day = 24 hours × 2 × (30 minutes)

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Divide the number of total seconds late by the number of 30-minutes passed.

That is, the number of total seconds late= 468 seconds ÷ 156

= 3 seconds  

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To learn more about clock problems visit:

brainly.com/question/27122093.

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